Question

A block of mass m = 6.04 kg is attached to a spring with spring constant k = 1572 N/m and rests on a frictionless surface. The block is pulled, stretching the spring a distance of 0.170 m, and is held still. The block is then released and moves in simple harmonic motion about the equilibrium position. (Assume that the block is stretched in the positive direction.) (a) What is the frequency of this oscillation? 2.57 Hz (b) Where is the block located 3.24 s after it is released? (Give the displacement from the equilibrium. Include the sign of the value in your answer.) -0.0690772304 x Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m (c) What is the velocity of the mass at that time? (Indicate the direction with the sign of your answer.) m/s

Answer 1

KE 1592 N/m m= 604 kg A = 0.170 m Last (9) f= 2.57 Hz To 172) 2= A Som/wtfnh B) at, t = 3.24 s x= 0.170 Sm( 20x2.52x 3.24 + 1/2 0.0788 m a = va Awo Cas(wt12) v = -2.43 mis 2