Question

Suppose a certain satellite has a highly eccentric orbit about Earth. At its greatest distance (apogee),...

Suppose a certain satellite has a highly eccentric orbit about Earth. At its greatest distance (apogee), it is 1487 km above the surface of Earth. At its closest approach (perigee), it is 737 km above Earth's surface. If it is moving at 7 km/s at apogee, what is its speed, in m/s, at perigee? Assume four sig figs.

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Answer #1

speed of satellite at Perigee can be calculated using Orbital speed Formula

Orbital speed at a height h is V=\sqrt{\frac{GM}{R+h}}

Given isht of apoge asove sur fea ha148 lem ei of Pegee av tuu Curfe te of t 3 lem veloiof Setelll at Perigee Vp ctealitisevoR 638 Cm ha=1 km, hp= 724 c in eauton we pt Rthp Rtha 63 8 37 715 165 = ০:৭5 0195

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