write a 2-step mechanism to convert the pre-catalyst above to the active Pd catalyst upon the...
2. The molecule below is currently sold as a pre-catalyst for Buchwald-Hartwig coupling reactions. Cyap MeHN-PO-OMS a. What is the oxidation state of the Pd?
what transformation needs to occur to convert the Pd-catalyst
added, Pd(PPh3)4, to the active catalyst A? what number(s) could n
equal in Pd0Ln?
0 1. The following reaction was recently reported along with a proposed catalytic cycle below: co Pd(PPhg) (1 mol %) CsOAC (1.0 equiv) THF, 60 °C, 16 h Na 32 examples up to 99% yields , co PdLI NHR ACOH CO2 COAC NHRC
5. Consider the reaction below. Write the complete stepwise mechanism for the reaction shown above. Show all intermediate structures and all electron flow with arrows. но он base catalyst ant 6. Give the major organic product(s) for the following reactions or sequence of reactions. Show all relev stereochemistry. Answer only 5 parts. If you think reaction de a.
3. Draw a stepwise, detailed mechanism for the acid-catalyzed hydration reaction in question 2 above. Use curved arrows to indicate the flow of electrons. (Note: use hydronium ion, H307, in your mechanism to indicate "acidic water"). (6 pts) 4. Draw a stepwise, detailed mechanism for the reaction below. Use curved arrows to indicate the flow of electrons. (Hint: think of this reaction as a combination of addition of HX (step 1) and hydration (step 2)]. In the second step, an...
B3: The following optically active oone optically active, one with no optical ac alkene, upon hydrogeraito explain this observation. n, yields two 4 pts H2 2 different products Pd/C CH3 B4: 1,3-butadiene, when treated with HBr, gives a mix of two product neither of which is 4-bromobut-1-ene. Predict both these products using mechanism that involves a single carbocation intermediate: 4 4-bromobut-1-ene Anot formed! HBr C5: Terminal alkynes are moderately acidic synthetically. When pent-1-yne is treated with a strong base [sodium...
Provide a mechanism that explains formation of the following products. Draw step 1 of this mechanism. Include lone pairs and formal charges in the mechanism. Draw out explicitly only the hydrogen of the H_3O^+. Draw step 2 of this mechanism. Include all lone pairs and formal charges in the mechanism. Do NOT draw out any hydrogen explicitly. The product of the above mechanism step has a resonance structure that leads to the formation of the second product. Draw the resonance...
Could you please draw a mechanism for the above reaction
Pd(OAc)2 TBAB K2CO3 . + H0 محBr V TOME Me0 5-phenyl-2-hydroxyacetophenone
2. Briefly explain why ethanol, and not hexane, was used as a solvent in this reaction? 3. Why it is necessary to filter the crude coupling product through a column of anhydrous MgSO4? 4. Briefly explain why aryl bromides and iodides, rather than aryl chlorides or fluorides, are typically used as substrates in Pd-catalyzed coupling reactions. 5. Propose a synthesis for the molecule A shown below, using benzene, phenyl boronic acid, tert-butyl bromide and any inorganic reagents needed. A retrosynthetic...
The mechanism for number 2 please
Polymers11 2. Write the reaction mechanism (showing arrows) of the synthesis of polystyrene. 4pts Include and show arrows in 2 initiation steps with benzoyl peroxide forming the phenyl radical. (this is shown in Figure 9 of the lab- just add all arrows) • A propagation step of the styrene (the monomer) and phenyl radical. • A second propagation step showing polymer growth by reacting styrene and the radical product of first propagation step. A...
(i) The reaction above is purposed to occur in 3 steps. From thelist select the mechanism description that is associated with theindicated step (assume all steps are in the forward direction). (a) The alkyloxonium ionis protonated as the bromide ion is formed. (b) The bromide ion attacks thecarbocation. (c) The alcoholic oxygen attacks thecarbocation. (d) The alcoholic oxygen is protonated as thebromide ion is formed. (e) A water molecule attacks thecarbocation. (f) A water molecule is formed at the sametime...