Question

Sand moves without slipping at 6.0 m/s down a conveyer that is tilted at 15∘. The sand enters a pipe h = 2.6 m below the end of the conveyer belt, as shown in the figure (Figure 1).

What is the horizontal distance d between the conveyer belt and the pipe?

Express your answer to two significant figures and include the appropriate units.

6 m/s 15°

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Answer #1

At the end of the conveyor belt sand has free fall under gravity. So we can use the equation of motion in a given plane to find the horizontal distance d.

Calculation is as shown below.

A s shown n ia 15o V : mo tion In hoiaontal 丁n venti cal dire ction : 6 CosIs V1553 m Using eau, at on。f motion ;n wrfond directon 2. nd 、t = 0.5873e c time fo hom3entel asvell a vertica) mo tion of Samd is same . Cos(us X0-58 so, ho.si3ontat olistance, d: uXt-娛vasts。) Xo.s87 3. m

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