Question

Calculate the solubility at 25°C of AgCl in pure water and in a 0.0180 M AgNO, solution. You'll find K, data in the ALEKS Datatab Round both of your answers to 2 significant digits. solubility in pure water: 0 . solubility in 0.0180 M AXNO, solution:

Answer 1

(1) Kap of Agd= 1.764 1070 Agde Agtede s 5 KAPF (Age). (at) 1.76410t0 - (5) (3) 5- 1.33x10-5 M In g/L = sx molor man of Agd - 1.338105 x 143 = 1.9 x 103 g/L b) Aguk Age e uo S40.0180 s due to AgNO3 KAP= (Agf). Cuo). - 1.76X10 to = (sto.0180). (3) Sto.0180 u 0.0180, as kop do very less so, 's' will be very small and can be neplected. 7 1.76X10 10 = (0.0160) (5) = 9.8x 10 M Ing/l = 9.8x109 x 143 = 1.48 106 g/L

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