Explain why the 0.10 mol L -1 sodium hydroxide solution could not have been prepared by weighing out 1.00g sodium hydroxide, dissolving this in water and making up to 250 ml.
Given that amount of NaOH = 1.00 g
Number of moles NaOH = amount in g / molar mass
= 1.00 g/ 39.997 g/mol
= 0.0250 moles
Molarity = number of moles / volume in L
=0.0250 moles /250 ml *1 L/1000 ML
= 0.10 mole/ L o r M
Explain why the 0.10 mol L -1 sodium hydroxide solution could not have been prepared by...
Explain why the 0.10 mol L^-1 sodium hydroxide solution could not have been prepared by weighing out 1.00g sodium hydroxide, dissolving this in water and making up to 250 ml.
Explain why the 0.20 mol L -1 sodium hydroxide solution could not have been prepared by weighing out 2.00g sodium hydroxide, dissolving this in water and making up to 500 ml.
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