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Explain why the 0.10 mol L -1 sodium hydroxide solution could not have been prepared by...

Explain why the 0.10 mol L -1 sodium hydroxide solution could not have been prepared by weighing out 1.00g sodium hydroxide, dissolving this in water and making up to 250 ml.

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Answer #1

Given that amount of NaOH = 1.00 g

Number of moles NaOH = amount in g / molar mass

= 1.00 g/ 39.997 g/mol

= 0.0250 moles

Molarity = number of moles / volume in L

=0.0250 moles /250 ml *1 L/1000 ML

= 0.10 mole/ L o r M

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