Explain why the 0.20 mol L -1 sodium hydroxide solution could not have been prepared by...

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Explain why the 0.20 mol L -1 sodium hydroxide solution could not have been prepared by...

Explain why the 0.20 mol L -1 sodium hydroxide solution could not have been prepared by weighing out 2.00g sodium hydroxide, dissolving this in water and making up to 500 ml.

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Answer 1

Answer #1

Mass of sodium hydroxide = 2 gram

Molar mass of NaOH = 40 g/mol

So moles = mass÷molar mass = 2/40 = 0.05 moles

Volume of solution = 500 ml = 0.5 L

So molarity = moles/volume = 0.05/0.5 = 0.1 mol/L

As we are getting molarity as 0.1 M

Hence, we can't prepare 0.2 mol/L

Amount of NaOH required is less

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Answer 2

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