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For each of the salts on the left, match the salts on the right that can be compared directly, using Kp values, to estimate s

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Answer #1

1. Silver iodide (AgI) :- CD (CaSO4 PbCO3)

2. Magnesium fluoride (MgF2) :- AB (Pb(OH)2 Zn(CN)2)

Explanation :-

1) The solubility equilibrium for AgI is

AgI() = AgTag) + Ting

And the solubility product is

Ksp = [Ag+][T]

We can compare AgI salt directly using Ksp with CaSO4 and PbCO3 salts as,

a) The solubilty equilibrium for CaSO4 is

CaSO4(s) = Caldo + so (aq)

And the solubility product is  

Ksp = [Ca²+1[S02-

b) The solubilty equilibrium for PbCO3 is

PbCO3(s) = Pb) + Co (aq)

And the solubility product is

Ksp = [Pb2+][CO-

---------------------

2) The solubility equilibrium for MgF2 is

MgF2(8) = M974) + 2F

And the solubility product is

Ksp = [Mg2+][F-14

we can compare MgF2 salt directly using Ksp with Pb(OH)2 and Zn(CN)2 as,

a) The solubilty equilibrium for Pb(OH)2 is

Pb(OH)2() = P67 + 20

And the solubility product is

Ksp = [Pb2+][OH-]

b) The solubilty equilibrium for Zn(CN)2 is

Zn(CN)2(s) = Zn2+ + 2C NGO

And the solubility product is

Ksp = [Zn2+][CN-]

----------------------------

Expression for K in term of solubility 's'

we have, AgI() = AgTag) + Ting ....(A)

and Ksp = [Ag+][T]

From equilibrium (A), if [Ag+] = s then [I-] = s

therefore, Kp = SXS =   

Again

we have, MgF2(8) = M974) + 2F ....(B)

and   Ksp = [Mg2+][F-14

From equilibrium (B), if [Mg+] = s then [F-] = 2s

Therefore,   Ksp = 5 x 2s) = 8 x 45+ = 45

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