please help 8) Determine the volume ofa 0.0246 M Li3PO4 solution that contains 11.8 grams of...

Question

Question

8) Determine the volume ofa 0.0246 M Li3PO4 solution that contains 11.8 grams of LI3PO4. (3pts)

please help

Answer 1

Answer #1

Molar mass of Li3PO4,

MM = 3*MM(Li) + 1*MM(P) + 4*MM(O)

= 3*6.968 + 1*30.97 + 4*16.0

= 115.874 g/mol

mass(Li3PO4)= 11.8 g

use:

number of mol of Li3PO4,

n = mass of Li3PO4/molar mass of Li3PO4

=(11.8 g)/(1.159*10^2 g/mol)

= 0.1018 mol

use:

M = number of mol / volume in L

0.0246 = 0.1018/ volume in L

volume = 4.14 L

Answer: 4.14 L

Answer 2

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