If 0.2997 g of potassium iodate (KIO3) are dissolved in 25.00 mL of distilled water, what...
If 0.2997 g of potassium iodate (KIO3) are dissolved in 25.00 mL of distilled water, what is the resulting molarity (M)? Give a brief explanation about why this is a very precise concentration to use. In other words, what makes potassium iodate such a good reagent with which to work in lab?
Homework Answers
firstly, we calculate the molarity of potassium iodate.
since , Molarity = no. Of mole/ volume (in Litre)
So, number of moles of potassium iodate= weight in g / molar mass.
= 0.2997/214 = 0.0014
And volume = 25 ml/1000l = 0.025 Litre.
Therefore, Molarity M= 0.0014/0.025 = 0.056 mol/litre.
Now, Why makes potassium iodate such a good reagent ??
the answer is -
Since potassium iodate is a salt of iodine , and it is quite stable reagent.it has much higher shelf life. It can be stored in lab and can be used for a long time.
As well, potassium iodate is a thyroid blocking agent and also it can be used as a maturing agent in baking sometimes.
These unique properties makes potassium iodate a good reagent with which to work in lab.
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