[Na+] = 0.0206 M
1 mol of Na2CO3 has 1 Na+
So,
[Na2CO3] = [Na+]/2
= 0.0206 M / 2
= 0.0103 M
volume , V = 4.746*10^2 mL
= 0.4746 L
use:
number of mol,
n = Molarity * Volume
= 1.03*10^-2*0.4746
= 4.888*10^-3 mol
Molar mass of Na2CO3 = 105.99 g/mol
use:
mass of Na2CO3,
m = number of mol * molar mass
= 4.888*10^-3 mol * 1.06*10^2 g/mol
= 0.5181 g
Answer: 0.518 g
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