![In the estimation of the chloride why is excess silver nitrate added to the sample?[2] Excess AgNO3](http://img.homeworklib.com/questions/09b3b280-72f6-11ea-8f11-f59a7e1d631b.png?x-oss-process=image/resize,w_560)
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Excess AgNO3 is added so that all chloride ions react with it and remaining Ag+ ions are back titrated to determine the concentration of chloride ions reacted.
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In the estimation of the chloride why is excess silver nitrate added to the sample?[2] Excess...
Silver nitrate is reacted with excess copper (II) chloride, producing solid silver chloride precipitate. If 25.5g...
Silver nitrate is reacted with excess copper (II) chloride, producing solid silver chloride precipitate. If 25.5g of silver nitrate is reacted and there is a 77.0% yield of silver chloride, how much silver was initially present? AgNO3 (s) + CuCl2 (aq) → AgCl (s) + Cu(NO3)2 (aq)
When solutions of calcium chloride and silver nitrate are mixed, silver chloride and calcium nitrate are...
When solutions of calcium chloride and silver nitrate are mixed, silver chloride and calcium nitrate are produced. CaCl2 + 2 AgNO3 --> 2 AgCl + Ca(NO3)2 How many grams of silver chloride are formed when 59 grams of AgNO3 react with excess calcium chloride? Please include units in your answer and round to 2 decimal places. Answer: Check Next page
For the following reaction, 5.09 grams of iron(II) chloride are mixed with excess silver nitrate Assume...
For the following reaction, 5.09 grams of iron(II) chloride are mixed with excess silver nitrate Assume that the percent yield of iron(II) nitrate is 93.4% Iron(II) chloride(aq) + silver nitrate(aq) iron(II) nitrate(aq) + silver chloride(s) What is the ideal yield of iron(II) nitrate? What is the actual yield of iron(II) nitrate? grams grams Submit ANSWER Retry Entire Group 2 more group attempts remaining The equation for this reaction is: FeCl2(aq) + 2 AgNO3(aq) - Fe(NO3)2(aq) + 2 AgCl(s)
046. 0.12 g of sample containing chloride ions requires 20 mls of O.IM KSCN when 25...
046. 0.12 g of sample containing chloride ions requires 20 mls of O.IM KSCN when 25 mis prepared AgNO, was added to the Sample solution. 25mls of prepared AgNO, requires 31.25mls of 0. IM KSCN. Calculate the percent of chloride in your sample. [8] In the estimation of the chlo on of the chloride why is excess silver nitrate added to the sample?[2]
I need help with questions 3 and 4!! 3. Calculate the normality of the silver nitrate...
I need help with questions 3 and 4!!
3. Calculate the normality of the silver nitrate solution and percent chloride in the sample: 352.4 mg pure KCl require 48.33 ml AgNO3 solution 323.3 mg of unknown requires 32.02 ml AgNO3 solution Calculate the titration error. 4. A sample of silver alloy weighing 984.6 mg was dissolved in nitric acid. The solution was neutralized, and 252.2 mg of pure NaCl added. The excess chloride required 19.09 ml of 0.0935 N AgNO3...
For the following reaction, 4.96 grams of iron(II) chloride are mixed with excess silver nitrate. The...
For the following reaction, 4.96 grams of iron(II) chloride are mixed with excess silver nitrate. The reaction yields 5.72 grams of iron(II) nitrate. iron(II) chloride (aq) + silver nitrate (aq) ---> iron(II) nitrate (aq) + silver chloride (s) a. What is the theoretical yield of iron (ll) nitrate? b. What is the percent yield of iron (ll) nitrate?
if 12.58 mL of silver nitrate soluation combines with an excess of potassium chloride solution to...
if 12.58 mL of silver nitrate soluation combines with an excess of potassium chloride solution to yield 0.05885 mol of precipitate, what is the molarity of the silver nitrate solution?
a When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of...
a When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of solution according to the equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq) Part A What mass of silver chloride can be produced from 1.51 L of a 0.293 M solution of silver nitrate? Express your answer with the appropriate units. b. The reaction described in Part A required 3.54 L of sodium chloride. What is the concentration of this sodium chloride solution? Express your answer with the appropriate units.
Calculate the volume in m) of silver nitrate solution that will be needed for the precipitation:...
Calculate the volume in m) of silver nitrate solution that will be needed for the precipitation: normally the amount of silver nitrate required to precipitate all of the chloride in the sample is found by a trial and error process. However, to speed up the experiment, assume a sample mass of 0.1479 g, and that sample contains approximately 55.0% chloride ion by mass (some samples may contain more, some less), and calculate what volume of 0.100 M AgNO3 needs to...
When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of solution according t...
When solutions of silver nitrate and sodium chloride are mixed, silver chloride precipitates out of solution according to the equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq) A.) What mass of silver chloride can be produced from 1.73 L of a 0.278 M solution of silver nitrate? B.)The reaction described in Part A required 3.26 L of sodium chloride. What is the concentration of this sodium chloride solution
When solutions of calcium chloride and silver nitrate are mixed, silver chloride and calcium nitrate are produced. CaCl2 + 2 AgNO3 --> 2 AgCl + Ca(NO3)2 How many grams of silver chloride are formed when 59 grams of AgNO3 react with excess calcium chloride? Please include units in your answer and round to 2 decimal places. Answer: Check Next page
For the following reaction, 5.09 grams of iron(II) chloride are mixed with excess silver nitrate Assume that the percent yield of iron(II) nitrate is 93.4% Iron(II) chloride(aq) + silver nitrate(aq) iron(II) nitrate(aq) + silver chloride(s) What is the ideal yield of iron(II) nitrate? What is the actual yield of iron(II) nitrate? grams grams Submit ANSWER Retry Entire Group 2 more group attempts remaining The equation for this reaction is: FeCl2(aq) + 2 AgNO3(aq) - Fe(NO3)2(aq) + 2 AgCl(s)
046. 0.12 g of sample containing chloride ions requires 20 mls of O.IM KSCN when 25 mis prepared AgNO, was added to the Sample solution. 25mls of prepared AgNO, requires 31.25mls of 0. IM KSCN. Calculate the percent of chloride in your sample. [8] In the estimation of the chlo on of the chloride why is excess silver nitrate added to the sample?[2]
I need help with questions 3 and 4!!
3. Calculate the normality of the silver nitrate solution and percent chloride in the sample: 352.4 mg pure KCl require 48.33 ml AgNO3 solution 323.3 mg of unknown requires 32.02 ml AgNO3 solution Calculate the titration error. 4. A sample of silver alloy weighing 984.6 mg was dissolved in nitric acid. The solution was neutralized, and 252.2 mg of pure NaCl added. The excess chloride required 19.09 ml of 0.0935 N AgNO3...
Calculate the volume in m) of silver nitrate solution that will be needed for the precipitation: normally the amount of silver nitrate required to precipitate all of the chloride in the sample is found by a trial and error process. However, to speed up the experiment, assume a sample mass of 0.1479 g, and that sample contains approximately 55.0% chloride ion by mass (some samples may contain more, some less), and calculate what volume of 0.100 M AgNO3 needs to...
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