Question

since hydrogen and neon have the same number of orbitals

CHE 101 Laboratory Manual Exp. 8: Solutions Page 133 B REPORT FORM: Name 100.00 g of an aqueous solution contains 14.00 g of KCI.. The density of the solution is 1.081 g/mL. Show ALL calculations. 3. a. What is the molality of KCI? 1mde ke 14.00gkel 74.55 0.1879 mdanty moles salule Lsolunon Soln/Imi Sole 0.097515 b. What is the molarity of KCI?

Answer 1

③ Molality = moles of solute 0 kg of solvent moles - mass of Soute . . molar mass of Solute 7 molan mass of kc = 74.55 g/mol. ... moles of kc = 14.000 - 74.55 g mol- = 0.1878 moles. i venst Solvent = 100,:00g < 0.100 119; + ide molality = 0.1878 mole = 1.878 mol kg 0.100 kq os socio - C1.878m!!; Ano wek 3 molality.= 16878m. calist in die w at in die pot. Scanned with CamScanner

molarity = moles of solute o volume of solution in L mass = 100.0g density = 1008 gimi density = mass Volume Volume = _mass I density : 1oo.ob 1.081 gmi- = 92.51 mL =000250 = 0.0925 L molarity = 0.1878 mode 0.09251 - L = 2.03 mol/L = 2.03 M. | Molarity = 2.03 m cs Scanned with CamScanner