Option 1:
Delta H is negative.
So, heat is released and the reaction is exothermic.
Option 2:
Since beaker is getting warmer, the reaction must have released the heat.
So, this is exothermic reaction.
Option 3:
Here heat is added on reactant side.
So, heat is being absorbed.
So, this is endothermic reaction.
Option 4:
Here heat is added on product side.
So, heat is being released.
So, this is exothermic reaction.
Answer: option 3
Question 13 (5 points) 13. Which of the following is an ENDOTHERMIC reaction? SF4(g) + 2...
4. (14 pts) Calculate AHr (kJ/mole) for the reaction CaHlg)+ 6 F2(g) >2 CFg) + 4 HF(g) AH (kJ/mole) ? Using only the following data AH (kJ/mole) H2(g)+ F2(g) C(s) + 2 F2(g) 2 C(s)+ 2 H2(g) 2 HF(g) -537.0 -680,0 CF4(g) C2H4(g) + 52.3
Given the following equation: 20F2(g) + 2 S(s) --> SO2(g) + SF4(g) AHrxn=-319.5 kJ/mol What is the AHrxn for the following equation: (3/2) SO2(g) + (3/2) SF4(g) --> 3 OF2(g) + 3 S(s) Write answer to three significant figures.
need help with all
Predict if the following reactions are exothermic or endothermic a) 2 H2(g) + O2(g/> 2 H2O(g) ΔΗ -484 kJ b) 2 Al(s) + Fe2O3(s) → 2 Fe(s) + Al2O3(s)AH =-852 kJ c) 2 H2O(g) 2 H2(g) + O2(g)AH :484 kJ d) 2 NH3(g) → N2(g) + 3 H2(g)AH = 92.2 kJ e) H2O(g) H2O(l) ΔΗ--44 kJ
Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol
2: Given: 1 S(s) + 2 F2(g) → 1 SF4 (8), AH = -774.9 kJ 2 S (s) + 3 O2(g) → 2 SO 3 (g), AH = -791.44 kJ On the basis of this information, calculate the heat change for the reaction 2 SF4 (8) + 3 O2(g) +2 SO 3 (8) + 4 F2 (g) OD: 758.4 kJ OA: -868.9 kJ OB: 714.0 kJ OC: -714.0 kJ OE: 1505.4 kJ
Given the following data: S(s) + 02(8) -> SO3(g) AH = -395.2 kJ 2SO2(g) + O2(g) + 2503(g) AH = - 198.2 kJ Calculate AH for the reaction: S(s) + O2(g) SO2(g) +296.1 kJ -494.3 kJ -296.1 kJ 0 -197.0 kJ -593.4 kJ
1.(3pts) Use the following data to determine the AH of > 8 CO (g) +5 H2O() 2 C Hiog) +13 O2(g) AH (KJ/mol) Substance AH (kJ/mol) Substance Data: -104.0 CaH&(g) CHHОН() CH12(g) CH&(I) НО) Со N2(g) С.Н.8) CH2OH(I) -239.0 C&Hio(g) C&H12(I) H2O(g) CO(g) O2(g) 20.9 -201.0 -146.44 -126.15 +12.0 -156.4 285.83 -241.82 -393.51 -110.53 0
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
1(3pts) Use the following data to determine the AH of > 8 CO (g) +5 H2O(I) 2 C.Hidg)+13 0:(g) AH (KJ/mol) Substance AH(kJ/mol) Substance Data: С-Н. () CH OH(g) C.Hi2(g) С.Н.0 Н.о0 со, N2(g) -104.0 -201.0 -146.44 +12.0 -285.83 С-Н.В) CH,OH() С.Н.о(8) C&Hi2(() H.O(g) CO(g) O:(g) 20.9 -239.0 -126.15 -156.4 -241.82 -393.51 -110.53
5. (20 pts) Consider the following reaction OF2(g) + H2O(g) ---> 2 HF(g) + O2(g) AH.(kJ/mole)=-318 kJ/mole (a) Using this information along with data in the appendix of your textbook, calculate AH (OF,(g)) in kJ/mole at 25°C. (b) If 15.0 g of OF2(g) and 10.0 g of H2Og) react, how much heat, expressed in kJ is released? Hint: First calculate the limiting reagent.