Question

please show work and clarify if it is products - reactants or reactants - products

Blackline Master 5.3-1 NAME: Dadline Mur 5,34 DATE 1/11/19 5.3-1 Calculating Enthalpy Change from Bond Energies Use the table below to answer the following questions. Table 1 Average Bond Energies (kJ/mol) Bond Energy 432 565 Energy 154 H-H H-F C-H C-O 413 Bond F-F 0-H CI-CI C-C CO C=O (for CO2(g)) 0-0 358 467 239 614 745 799 CO C-C C-ci 1072 347 339 495 Calculate the enthalpy change from bond energies for each of these reactions: 1. Hz(8) + F2(g) → 2 HF(g) AH = 432 2. CH.(g) + 20() CO2(g) + 2H20 (8) AH 3. CO(g) + 2H2(g) - CH,OH(1) AH- 4. 2H2(g) + O2(g) -- 2H2O(g) AH 5. 2H2O(g) - 2H2(g) + O2(g) 4H

Answer 1

AH = E Creactant Bond energies) – Ecproduct- bond energies) Ace -> 2 H-F H-H (g) + F-F (9) AH = (422 +154) – 2(565) = -563 kg/mol 2) #-é-H + 2 0=0 → 0=C=0 + 2 H OH OH AH = (4 -4 + 2 =o)-(so + 2 e-H) - [4(413) +2 (495)) - ((2x299) + (2x467)] - 110 kJ/mol

3) c=0 + 2H- H H -C-0-H w AH = (c=0 + 2 H-H) - [(3XC-H) + (-0) + (0-H)] = (1072 + 2(432)] – [13x413) + 358 +467] = -128 kJ/mol 4) AH = (a(432) + 495)-(2(467)) AH = 425 kJ/mo). 5) AH = -425 kJ/mol.