1)
A is the ground state.
Energy there is 300 zJ
Answer: 300 zJ
2)
B is the 1st excited state.
Energy there is 600 zJ
Answer: 600 zJ
3)
Since electron is moving from higher energy state to lower energy state, the photon is released
Answer: emitted
4)
Energy of this transmission = EC - EB
= 800 zJ - 600 zJ
= 200 zJ
= 200*10^-21 J
= 2.00*10^-19 J
use:
E = h*c/lambda
2*10^-19J =(6.626*10^-34 J.s)*(3.0*10^8 m/s)/lambda
lambda = 9.94*10^-7 m
= 994 nm
Answer: 994 nm
14001 1200+ 1000+ 800+ energy (2) 600 L Use this diagram to complete the table below....
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