Consider the value of t such that the area under the curve between −|t| and |t| equals 0.9.
Step 2 of 2 : Assuming the degrees of freedom equals 11, select the t value from the t table.
Solution:-
Given that,
degrees of freedom = 11
Using t table,
P( -t < T < t) = 0.9
= P(T < t) - P(T <-t ) = 0.9
= 2P(T < t) - 1 = 0.9
= 2P(T < t) = 1 + 0.9
= P(T < t) = 1.9 / 2
= P(T < t) = 0.95
= P(T < 1.796) = 0.95
= t ± 1.796
Consider the value of t such that the area under the curve between −|t| and |t|...
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