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Look at image, thank you.Scores for a common standardized college aptitude test are normally distributed with a mean of 510 and a standard deviation o

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Answer #1

a) P(X > 587.8)

\small = P(z > \frac{587.8-510}{110})

= P(z > 0.70)

= 0.2397

b) P(M > 587.8)

\small = P(z > \frac{587.8-510}{110/\sqrt{8}})

= P(z > 2)

= 0.0227

c) Option B is correct.

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