Solution :
Given that ,
mean = = 72
standard deviation = = 12
n = 36
= 72
= / n = 12/ 36 = 2
P( > 69) = 1 - P( <69 )
= 1 - P[( - ) / < (69-72) /2 ]
= 1 - P(z <-1.5 )
Using z table
= 1 - 0.0668
= 0.9332
probability= 0.933
Scores on a standard test of mechanical aptitude are normally distributed with a mean of 72...
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