Question

Warner Chemical Equilibrium Page 6 of 11 Assuming the density of your initial acid solution is 1.0 g/ml, what is the concentration (in molarity) of the diluted acetic acid solution? Show your work and include units. Hint: An initial 45% w/w solution (w/w means 4.5 g of acid per 100 g of solution) of CH3COOH (MW - 60.05 g/mol) was diluted by placing 0.5 mL into 80 mL of water to produce a final diluted solution with a total volume of 80.5 mL (You will also need to add in the volume of the indicator to your total volume, so it will be slightly higher Thaln 80.5 mL) Use this information to first solve for the % w/w of the diluted acetic acid solution and then converting % w/w to molarity

Answer 1

4. 54. ole solution de 4.69 of Chicoom in too g Water Total volume of the solution of aid = 0.5ml Mestout cokhion 2 xelum density Suppose we have loog of initial solution. The volume of initial solution - 100ml mass of child in solution 4.59 moles of aid = 4.54 0.075 mol . 10.os Molarity of initial solution 0.075 xlouo = 0.75m 100 Volume of final saletion 81.0m (Let volume of indicator =0.5mm miv, = M₂ VL 0.75 x0.5 = M, 81.0 M2 - 0.75X0.5 0.00463m Any 81.0