Can someone give step by step calculations with neat handwriting please
Can someone give step by step calculations with neat handwriting please Thermodynamics Free energy and chemical...
Thermodynamics Free energy and chemical equilibrium Quiz: Te equilibrium constant for the reaction N29) + O22) + 2 NO 262) Decreases from 1.5 * 109 at 430 °C to 23 at 1000°C. From these data: a-calculate enthalpy change of this reaction; b- equilibrium constant at 1500 °C.
Thermodynamics Free energy and chemical equilibrium Quiz: Te equilibrium constant for the reaction Na + O2 + 2 NO 200 Decreases from 1.5-10 at 430 °C to 23 at 1000°C. From these data: a - calculate enthalpy change of this reaction; b-equilibrium constant at 1500 °C
Thermodynamics Free energy and chemical equilibrium Quiz: Te equilibrium constant for the reaction N20 +020) + 2 NO 262 Decreases from 1.5 x 103 at 430 °C to 23 at 1000°C. From these data: a-calculate enthalpy change of this reaction; b-equilibrium constant at 1500 °C.
Thermodynamics Free energy and chemical equilibrium Quiz: Te equilibrium constant for the reaction N20 + 029 + 2 NO 200) Decreases from 1.5x 105 at 430 °C to 23 at 1000°C. From these data: a - calculate enthalpy change of this reaction; b- equilibrium constant at 1500 °C.
Hello, please help thank you Thermodynamics Free energy and chemical equilibrium Te equilibrium constant for the reaction N2 + O2 2 NO 20 Decreases from 1.5x 103 at 430 °C to 23 at 1000°C. From these data: a - calculate enthalpy change of this reaction; b- equilibrium constant at 1500 °C.
can someone give step by step calculations with neat handwriting 2. Lead poisoning. Treatment for lead poisoning provided by intravenous injection of EDTA in the blood of patient. The concentration of EDTA is 1.0x10^-7 M, and the formation constant (Kf) of lead-EDTA complex is 2.0x10^18. What is the concentrati ratio of the free (potentially toxic) lead ions and lead-EDTA complexes (less toxic) in the blood?
Can you please solve 3 and 4 with neat handwriting ? Could you explain each step so I can understand? Q3) Using the following data that relates to the formation of vacancy defects in a metallic sample. Determine the following: a) The energy for defect formation in (V) b) The equilibrium number of vacancy defects per cubic meter at 1000 C T°C] Nv/ ml 750 5.7 x 10 1000 ? 1500 5.8 x 1017 Q4) Draw a series of schematics...
Thermodynamics of the Dissolution of Borax Prelaboratory Assignment 1. The standard free energy change for the formation of two moles of H:0 (l) in a strong acid-strong base neutralization reaction at 25°C is -799 kJ. H30+ (aq) + OH(aq) → 2H20 (1AG° -79.9 kJ a. Calculate the equilibrium constant for the reaction b. Explain the chemical significance of the calculated equilibrium constant for the neutralization reaction. c. The standard enthalpy change, AH, for a strong acid-strong base reaction is -57.8...
Can someone please step by step explain how to answer every question. Thank you Question 20 For an equilibrium reaction, AG=0 kJ at 253.7 K. If the equilibrium constant is 80.0, what is the standard change in Gibb's free energy (kl) of this reaction? Question 21 For an equilibrium reaction, AG = 0 kJ at 472.5 K. If the standard change in Gibb's free energy of this reaction is 0.670 kJ, what is the equilibrium constant? Question 22 For an...
Can someone give step by step calculations with neat hand writing please. 2 other 2. (25 points) Calculate the values of Gibbs free energy change for the reduction of iron ore with hydrogen gas: page Fe2O3(s) + 3 H2(g) = 2 Fe(s) + 3 H2O®)isk for Thermodynamic properties at 25 °C 6° -4° - TAS Fe2O3(s) React HQ React Fes) for H2O Prod AH®, kJ/mol -824.2 0 . 0 -241.8 IS, J/(mol·K) 87.4 130.6 27.3 188.8 Is process spontaneous at...