Question

Problem II: We have a deep tank of still water open at the top. At a depth of 194m below the free surface of the water the tank extends horizontally outward so that the tank has a flat horizontal surface S with water on the underside with no air gap Q5. What is the constant B found by evaluating Bernoulli's equation at the upper surface of the water in the tank? This surface is at an elevation y+194m above the lower surface S and the water is not moving significantly. The upper water surface is open to the atmosphere, so the pressure there is p atm (A) B= 2.002 × 106 Pa (B) B= 2.006 × 106 Pa (C) B= 2.005 × 106 Pa (D) B = 2.003 x 106 Pa (E) B-2.004 x 106 Pa Q6. What is the pressure p at elevation in the water y (the level of the surface S) and at a point where the water is stationary? (Assume for this question: B = 2 x 106 Pa) (A) 3.0 x 106 Pa (B) 1.0 x 106 Pa (C) 4.0 x 106 Pa (D) 2.0 x 106 Pa (B) 0.5× 106 Pa Q7. As stated above, at elevation y 0 the tank spreads out to a larger diameter part that is covered by the sealed surface S. There is a small hole of radius a (a is much less than the diameter of the tank) in the horizontal surface S through which water is streaming upward. The pressure p in the water stream just after the water leaves the tank is patm because the stream is unconfined. What is the velocity vs of the water stream just after the water leaves the tank? (Assume for this question: B 2 x 10 Pa) (A) 124 m/s (B) 97m/s (C) 7m/s (D) 23m/:s (E) 62 m/s

Answer 1

gs Accoycding to given datca; OPhm A