Question

7. A solution is made by dissolving 0.02500 moles of Ba(OH)2 in enough water to make 750 ml of solution. What is the pH of the resulting solution?

Answer 1

2 + & Ba(OH)2 is a strong base. gn solution it dissociates fully nie as belon – Ba(OH) = Bat + 2040 According to the above equation we can see that 1 mol Ba (ot) dissociates to give 2 mol ot in Thus, 0.025 mol Ba(OH) will give 2x 0.025 mol = 0.05 mol ott ion Thus, No. of moles of ot in solution = 0.05 mol Again volume of the solution = 750 mL - 750 L = 0.75 L in Molaro 1000 concentration of ot in [OH-] = 0.05 mol 0.75 L = 0.067 mol/ - 0.067 M

u poh - – log [OH-] = -log (0.067) - 1.174 i pH = 14 - POH = 14 - 1.174 = 12.83 o pH of the resulting solution = 12.83 Ane