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please show calculations in writing
4. Two students prepare two cyclohexane solutions having the same freezing...
A. Freezing Point of Cyclohexane (Solvent 1. Mass of beaker, test tube (g) 2. Freezing point,...
A. Freezing Point of Cyclohexane (Solvent 1. Mass of beaker, test tube (g) 2. Freezing point, from cooling curve 3. Instructor's approval of graph 33010 B. Freezing Point of Cyclohexane plus Unknown Solute Trial 1 Parts B.1, B.3) Unknown solute no. Trial 2 (Part B.4 Trial 3 Part B.5 1. Mass of beaker, test tube, cyclohexane (g) 2. Mass of cyclohexane (g) 3. Tared mass of added solute (g) 4. Freezing point, from cooling curve CC) 5. Instructor's approval of...
Freezing points are lowered as a function of the number of moles of solute particles per...
Freezing points are lowered as a function of the number of moles of solute particles per kilogram of solvent. This is expressed mathematically with the following equation ATt Xkxi (mgolvending) where AT, is the amount by which the freezing point is lowered, Toute is the number of moles of solute, m ening is the mass of the solvent (in kilograms). ke is the freezing point depression constant which is specific to the solvent, and, i is the number of particles...
Did I do number 3 correctly? Calculate the total moles of solute present in each of...
Did I do number 3 correctly?
Calculate the total moles of solute present in each of the three (3) trials provided in the experimental data. Use the equation editor to show your calculations. 12pt Paragraph В І y A2 Tv -182.5 moles 0.04 0.04 0.0093002) Kg Soluent (AT) = KM) = (6.3 - 4.9) = 202 zmoles 0.07 -0.07 0.0093002) Kg Solvent moles 0.0679 .00930024.0093002) 0.00037201 1.4 20 0.07 = 3 20 20 moles 0.1190 .00930024.0093002) 0.00066101 IN 183.71 (AT)...
Need help solving the calculationss. please show work on a seperae piece of paper and show...
Need help solving the calculationss. please show work on a
seperae piece of paper and show all work.
Background information.
Experiment 1: Measure the Freezing Point of Pure Water 10 1. Volume of water (mL): 10 2. Mass of water (g): 3. Freezing Temperature (°C): 0 Experiment 2: Measure the Freezing Point of a Solution of an Unknown Substance 1. Mass of FP sample 1 (g): 2.00 si 2. Mass of sample and water (g): 12.000 3. Freezing Temperature (°C):...
PLEASE COMPLETE ASAP! PLEASE SHOW WORK FOR EACH TABLE CLEARLY AND IN CORRECT ORDER! I WILL...
PLEASE
COMPLETE ASAP! PLEASE SHOW WORK FOR EACH TABLE CLEARLY AND IN
CORRECT ORDER! I WILL GIVE YOU A GOOD RATING IF DONE CLEARLY AND
CORRECTLY :) FEEL FREE TO MAKE YOUR OWN TABLE SINCE THIS ONE DOES
NOT ALLOW YOU TO INPUT DATA.
UPDATE:
Someone asked which solvent is being used. It does not specify in
the data provided, it already gives the volume and the mass of the
solvent so you would use that to find the density....
Solute Mass(g) Observed Freezing Point (Celcius) m i Theoretical Freezing Point (Celcius) NaCl 2.94g -1 CaCl2...
Solute Mass(g) Observed Freezing Point (Celcius) m i Theoretical Freezing Point (Celcius) NaCl 2.94g -1 CaCl2 * 2H20 7.37g 0 C12H22O11 17.14g 0.5 100.0g of pure ice water freezing point 0.5 C Final Freezing Point -3 Your solvent mass should be the mass of the water and the mass of the ice You should use your observed freezing point of pure water to adjust the values for the observed freezing point of the solution, that will make comparing your observed...
PLEASE SHOW WORK FOR EACH TABLE CLEARLY AND IN CORRECT ORDER! I WILL GIVE YOU A...
PLEASE SHOW WORK FOR EACH TABLE CLEARLY AND IN CORRECT
ORDER! I WILL GIVE YOU A GOOD RATING IF DONE CLEARLY AND CORRECTLY
:)
DATA:
Sodium chloride
Freezing point of Water (°C)
0.00
Freezing point of NaCl (°C)
-4.40
Mass of solute (g)
5.89
Volume of Solvent, mL
100.0
Sugar
Volume of Solvent, mL
100.0
Freezing point of Sucrose (°C)
-1.70
Mass of solute (g)
34.05
Ethyl alcohol
Freezing point of E.G (°C)
-1.80
Mass of solute (g)
6.202
Volume...
I'm having trouble determining how to find delta T and the freezing point depression for Solutions...
I'm having trouble determining how to find delta T and the freezing point depression for Solutions #1 and #2. This is all the information I have. Please show all work. Thank you. Mass of test tube 24.7795 g Mass of tube + BZP 34.2490 g Mass of BZP used 9.4695 g Freezing point of pure BZP -9.80 kg/mL Solution 1 Solution 2 Mass of container and Sample 11.7366 g 11.7366 g Mass of container and Sample (after weighing) 11.0103 g...
Solute KMnO4 Soluble/Not Soluble in Water (A.1) Cyclohexane (A.2) Identify the Solute as Polar or Nonpolar...
Solute KMnO4 Soluble/Not Soluble in Water (A.1) Cyclohexane (A.2) Identify the Solute as Polar or Nonpolar (A.3) Sucrose Vegetable oil NaCl is soluble in water, but I, is not. Explain. State the general solubility rule concerning the polarities of a solute and solvent. Calculations B.4 Solubility is expressed as the number of grams of solute in 100 mL of water. Because you used a sample of 5.0 mL of water, the mass of the solute you measured out and the...
What is the relationship between the moles of solute and the mass of solute? Rewrite the molality expression in terms o...
What is the relationship between the moles of solute and the
mass of solute?
Rewrite the molality expression in terms of grams and molecular
weight.
Background:
Properties that depend on the concentration of particles in solution are called colligative properties. The number of particles in a solvent can affect the freezing or boiling point of solvent. To express the effect of concentration on freezing point or boiling point, molality is used in place of molarity. Molality (m) is the number...
A. Freezing Point of Cyclohexane (Solvent 1. Mass of beaker, test tube (g) 2. Freezing point, from cooling curve 3. Instructor's approval of graph 33010 B. Freezing Point of Cyclohexane plus Unknown Solute Trial 1 Parts B.1, B.3) Unknown solute no. Trial 2 (Part B.4 Trial 3 Part B.5 1. Mass of beaker, test tube, cyclohexane (g) 2. Mass of cyclohexane (g) 3. Tared mass of added solute (g) 4. Freezing point, from cooling curve CC) 5. Instructor's approval of...
Freezing points are lowered as a function of the number of moles of solute particles per kilogram of solvent. This is expressed mathematically with the following equation ATt Xkxi (mgolvending) where AT, is the amount by which the freezing point is lowered, Toute is the number of moles of solute, m ening is the mass of the solvent (in kilograms). ke is the freezing point depression constant which is specific to the solvent, and, i is the number of particles...
Did I do number 3 correctly?
Calculate the total moles of solute present in each of the three (3) trials provided in the experimental data. Use the equation editor to show your calculations. 12pt Paragraph В І y A2 Tv -182.5 moles 0.04 0.04 0.0093002) Kg Soluent (AT) = KM) = (6.3 - 4.9) = 202 zmoles 0.07 -0.07 0.0093002) Kg Solvent moles 0.0679 .00930024.0093002) 0.00037201 1.4 20 0.07 = 3 20 20 moles 0.1190 .00930024.0093002) 0.00066101 IN 183.71 (AT)...
Need help solving the calculationss. please show work on a
seperae piece of paper and show all work.
Background information.
Experiment 1: Measure the Freezing Point of Pure Water 10 1. Volume of water (mL): 10 2. Mass of water (g): 3. Freezing Temperature (°C): 0 Experiment 2: Measure the Freezing Point of a Solution of an Unknown Substance 1. Mass of FP sample 1 (g): 2.00 si 2. Mass of sample and water (g): 12.000 3. Freezing Temperature (°C):...
PLEASE
COMPLETE ASAP! PLEASE SHOW WORK FOR EACH TABLE CLEARLY AND IN
CORRECT ORDER! I WILL GIVE YOU A GOOD RATING IF DONE CLEARLY AND
CORRECTLY :) FEEL FREE TO MAKE YOUR OWN TABLE SINCE THIS ONE DOES
NOT ALLOW YOU TO INPUT DATA.
UPDATE:
Someone asked which solvent is being used. It does not specify in
the data provided, it already gives the volume and the mass of the
solvent so you would use that to find the density....
PLEASE SHOW WORK FOR EACH TABLE CLEARLY AND IN CORRECT
ORDER! I WILL GIVE YOU A GOOD RATING IF DONE CLEARLY AND CORRECTLY
:)
DATA:
Sodium chloride
Freezing point of Water (°C)
0.00
Freezing point of NaCl (°C)
-4.40
Mass of solute (g)
5.89
Volume of Solvent, mL
100.0
Sugar
Volume of Solvent, mL
100.0
Freezing point of Sucrose (°C)
-1.70
Mass of solute (g)
34.05
Ethyl alcohol
Freezing point of E.G (°C)
-1.80
Mass of solute (g)
6.202
Volume...
Solute KMnO4 Soluble/Not Soluble in Water (A.1) Cyclohexane (A.2) Identify the Solute as Polar or Nonpolar (A.3) Sucrose Vegetable oil NaCl is soluble in water, but I, is not. Explain. State the general solubility rule concerning the polarities of a solute and solvent. Calculations B.4 Solubility is expressed as the number of grams of solute in 100 mL of water. Because you used a sample of 5.0 mL of water, the mass of the solute you measured out and the...
What is the relationship between the moles of solute and the
mass of solute?
Rewrite the molality expression in terms of grams and molecular
weight.
Background:
Properties that depend on the concentration of particles in solution are called colligative properties. The number of particles in a solvent can affect the freezing or boiling point of solvent. To express the effect of concentration on freezing point or boiling point, molality is used in place of molarity. Molality (m) is the number...
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