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2. Use the given half reactions to "construct" an electrolytic cell. Cu2+ + 2 e +...
Consider the cell: Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v a) Write the cell reaction which occurs when the cell produces current and calculate Ecell. b) If each cell compartment contains 25.0 mL of the corresponding metal salt solution and 25.0 mL of 3.00 M NH3(aq) is added to the Cu2+ solution, Ecell = 0.68 v. Use these data to calculate Kf for Cu(NH3)42+. Cu2+(aq) + 4 NH3(aq) ⇄ Cu(NH3)42+
For the following cell what is the cell potential under standard conditions? Zn + Cu2+ → Cu + Zn2+ If Cu2+ + 2e- → Cu E° = 0.34V and Zn2+ + 2e- → Zn E° = -0.76 V
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
1. Voltage reading for Fe-Cu cell 0.60 V 2. Voltage reading for Fe-Zn cell 0.25 V 3. Voltage reading for Cu-Zn cell 0.80 V 4. Fe2+ reduction half-reaction and Esedº Ered 5. Cu2+ reduction half-reaction and Ered Ered 6. Zn2+ reduction half-reaction and Ered Ered 7. Redox reaction of Fe-Cu cell 8. Fe-Cu Ecelº Ecell = 9. Redox reaction of Fe-Zn cell 10. Fe-Zn Ecetº Ece 11. Redox reaction of Cu-Zn cell 12. Cu-Zn Eceitº Ecelº = Questions to consider...
A voltaic cell consists of a standard hydrogen electrode in one half-cell and a Cu/Cu2+ half-cell. Calculate [Cu2+] when Ecell is 0.22 VA voltaic cell consists of a standard hydrogen electrode in one half-cell and a Cu/Cu2+ half-cell. Calculate [Cu2+] when Ecell is 0.22 V
38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at the cathode and what is the Eceu? Fe2+(aq) + 2e → Fe(s) E°=-0.44 V Cu²+(aq) + 2e → Cu(s) E°= 0.34 V a) b) c) d) Cu2+(aq) + 2e → Cu(s), Ecell = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecel = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecell =-0.10 V Cu²+(aq) + 2e → Cu(s), Ecel = 0.10 V Cu²+ (aq) +...
For a standard electrolytic cell, a power source forces the reaction Cu + Zn2+ -> Cu2+ + Zn to occur. Determine the mass of copper that is plated out when a current of 10.0 A is passed for 30.0 minutes through a solution containing Cu2+.
Use the information given below to answer the questions about this standard electrochemical cell. ξo(V) Cu2+(aq) + 2 e- → Cu (s) + 0.34 Zn2+(aq) + 2 e-→ Zn (s) - 0.76 Mark each of these statements as True or False. a.) The concentration of Cu2+ decreases as the reaction proceeds. b.) The solid metal cathode decreases in mass. c.) Negatively charged ions flow from the salt bridge to the anode. d.) The electrons will flow from the anode to...
Given: Zn2+ (aq) + 2e Zn(s); E--0.76 V Cu²+ (aq) +20 Cu(s); E° -0.34 V What is the cell potential of the following electrochemical cell at 25°C? Zn(s) | Zn2+(1.0 M) || Cu2+(0.0010 M) Cu(s) a) greater than 1.10 v b) between 0.76 and 1.10 V c) less than 0.42 V d) between 0.00 and 0.76 V e) between 0.34 and 0.76 V
pls do all Page 12 of 14 36. (15 points) A spontaneous galvanic cell consists of one half-cell that e ontains Agia) and rea ad one half-cell that contains Cucs) and Cu2+(ag). The standard reduction reactions are listed below Cu2+(aq) + 2 e-→ Cu(s) +0.34 V Identify which half reaction is happening at the anode and the cathode reaction for this spontaneous galvanic cell. a. and write the gwerall Calculate E°cell for this reaction. b. for this reaction. Calculate Δ...