Question

Consider the cell:  Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v             a)...

Consider the cell:  Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v

            a) Write the cell reaction which occurs when the cell produces current and calculate Ecell.

b) If each cell compartment contains 25.0 mL of the corresponding metal salt solution and 25.0 mL of 3.00 M NH3(aq) is added to the Cu2+ solution, Ecell = 0.68 v. Use these data to calculate Kf for Cu(NH3)42+.

Cu2+(aq)  +  4 NH3(aq)     Cu(NH3)42+

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Answer #1

The cell is given below - Zn (S) / Zn2+ (0.20 m) // cu 2+ (0.20 m) / Cu (S) €° cu 2+ / eu = 0.34 V 7 Reduction, s potential -

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Consider the cell:  Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v             a)...
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