Hello is the answer 1.041 or 1.16
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Hello is the answer 1.041 or 1.16 point) Consider the following voltaic (galvanic) cell: Zn(s) 0.010...
Question 2 (1 point) Consider the following voltaic (galvanic) cell: Zn(s) | 0.010 mol/L Zn2+ (aq) || 1.0 mol/L Cu2+(aq) | Cu(s) What is the predicted cell potential when this cell is operated? 1.04 V 1.10 V 0.76 V 0.34 V 1.16 V
Given: Zn2+ (aq) + 2e Zn(s); E--0.76 V Cu²+ (aq) +20 Cu(s); E° -0.34 V What is the cell potential of the following electrochemical cell at 25°C? Zn(s) | Zn2+(1.0 M) || Cu2+(0.0010 M) Cu(s) a) greater than 1.10 v b) between 0.76 and 1.10 V c) less than 0.42 V d) between 0.00 and 0.76 V e) between 0.34 and 0.76 V
Consider the reaction corresponding to a voltaic cell and its standard cell potential. cell Zn(s) + Cu2+ (aq) + Cu(s) + Zn2+ (aq) E = 1.1032 V As What is the cell potential for a cell with a 2.573 M solution of Zn²+ (aq) and 0.1055 M solution of Cu²+ (aq) at 432.4 K?
Consider the reaction corresponding to a voltaic cell and its standard cell potential. Zn(s) + Cu2+ (aq) Cu(s) + Zn2+ (aq) ЕО cell = 1.1032 V What is the cell potential for a cell with a 2.440 M solution of Zn2+ (aq) and 0.1636 M solution of Cu²+ (aq) at 439.5 K?
Please show detailed steps. The standard emf for the following voltaic cell is 1.10 V: Zn(s)/Zn2 (aq)Cu+(aq)Cu(s) 4. (4 Pts) Calculate the equilibrium constant for the reaction: Zn(s)+Cu2 (aq) Zn2 (aq) + Cu(s)
Consider the reaction corresponding to a voltaic cell and its standard cell potential. Zn(s) + Cu²+ (aq) + Cu(s) + Zn2+ (aq) = 1.1032 V What is the cell potential for a cell with a 2.401 M solution of Zn2+ (aq) and 0.1776 M solution of Cu²+ (aq) at 420.4 K? Answer:
Consider the cell: Zn(s)ǀ(Zn2+(0.20 M)ǁCu2+(0.20 M)ǀCu(s) with Eº(Cu2+/Cu = 0.34 v and Eº(Zn2+/Zn) = –0.76 v a) Write the cell reaction which occurs when the cell produces current and calculate Ecell. b) If each cell compartment contains 25.0 mL of the corresponding metal salt solution and 25.0 mL of 3.00 M NH3(aq) is added to the Cu2+ solution, Ecell = 0.68 v. Use these data to calculate Kf for Cu(NH3)42+. Cu2+(aq) + 4 NH3(aq) ⇄ Cu(NH3)42+
V. The standard cell potential for the voltaic cell based on the reaction below is Cu 2+ + 2 e -----> Cu °E,Cu= -0.34 Volt + 2 e------> Zn OE, Zn = 0.76 Volt Zn2+ 1.1 volt 0.42 volt 1.0 volt 2.2 volt
tion 3 of 40 ) A voltaic cell employs the redox reaction: Zn (s) + Pb2+ (aq) — Zn2+ (aq) + Pb () where Pb2+ (aq) + 2e Zn2+(aq) + 2e Pb(s) E = -0.1262 V Zn(s) E = -0.7618 V The cell potential (Ecell) of this voltaic cell when [Pb2+1 = 1.10 M and [Zn2+) = 0.00110 Mis:
Consider the voltaic cell at 25 °C 21. Zn(s) | Zn2 (aq, 1.0 x 10 2 mol L-1) I Ce (ag, 1.0 mol L-1), Ce (aq, 1.0 x 102 mol L-') | Pt(s) in which the compartments have equal volume. What is the electromotive force of the cell when the circuit is closed and the reaction has advanced to the point that [Ce3]-0.2 mol L12 A) 2.48 V B) 2.43 V C) 1.24 v D) 2.54 V E) 0.957 V