Question

Find the equivalent capacitance Ceq of the combination of capacitors shown in the figure, where C1-0.625 μF, C2-10.0 μF , and C3-3.75 μF C.
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Answer #1

C1 and C2 are in the series

The capacitors are in the series then the operation will be =Ca

C1 C2/(C1 C2)

Ca 0.625 * 10/(0.625 10)

Ca= 0.588 micro F

Now Ca and C3 are in parallel

In parallel operation

Ceq = Ca + C3

Ceq= 0.588 + 3.75

Ceq= 4.338 micro F

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