Question

What is the expected mass of the product of the reaction of 0.0015 moles of 3,4-dimethoxybenzaldehyde and 0.0015 moles of 1-indanone with 0.05g of solid NaOH and addition of HCl solution afterwards? This is an aldol condensation (green chemistry) problem.

Answer 1

Question: What & the expected mass of the product of the reaction of 0.0015 moles of 3,4-dimethoxybenzaldehyde and 0.0015 moles. of I- Indanone with 0.059 of solid Nash and addition of Hcl Solution cefterhands? Solution: |- Indanore Molecular weisht = 280-32 ome 3.4-dimethoxy - benzaldehyde 0.0015 m O-0015 - Here both the Starting materials are (1.0 equir) of 3,4-dimethoxy benzaldehyde 0.0015 moles, means and 1 - Indlanone. How to Cakalate expected mass of product ? Theoritical Yield = limiting reagent mole & Molecular cut of product Whatever, they given compounds both are some moles, means Same equivalent So Theoritical Yield = 0.00154 280.32 = 0.42 g for 420 mg Ans: Expected mass of product is 4220mg) (or) 0.42(9).