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Starting from rest, a subway train accelerates to a speed of 20.0 m/s in tA20.6 seconds. The train travels at that speed for the next 21 seconds. Finally, the train decelerates steadily to a full stop over the next 10.3 seconds What is the trains acceleration at the beginning? 9709 m/s2 What is the trains deceleration as it comes to a stop? - 1.9417 m/s2 How far does the train travel overall? 729 m. At what time has the train traveled 486 m from where it started? t-30.6 (20.0 m/s is only 45 MPH, just sayin)

I'm not sure what I'm doing wrong for the last question.

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Answer #1

Applying equations of motion.

PAGE NO.: DATE: t. 2 2 0.9709 ) x (So, 2 Nlaus at un 以。 3. 911s

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