Given: A particle with a mass of 0.5 kg moves along the x-axis and is braked by a horizontal braking force that provides the following braking acceleration: Ax(vx) = -0.005 vx2 (m / s2)
The initial conditions at time t = 2 (s) are: x (2) = 25 (m) and vx (2) = 40 (m / s)
The question is to determine the specific time t* at which the x coordinate is given by x (t*) = 200 (m)
Given: A particle with a mass of 0.5 kg moves along the x-axis and is braked...
Given: A particle with a mass of 0.5 kg moves along the x-axis and is braked by a horizontal braking force that provides the following braking acceleration: Ax (vx) = -0.005 vx2 (m / s2) The initial conditions at time t = 2 (s) are: x (2) = 25 (m) and vx (2) = 40 (m / s) The question that is asked is to calculate the amount of labour that the braking force performs between t = 2 (s)...
A particle starts from rest at x = -1.8 m and moves along the x-axis with the velocity history shown. Plot the corresponding acceleration and the displacement histories for the 2.0 seconds. Find the time t when the particle crosses the origin. After you have the plots, answer the questions. Chapter 2, Practice Problem 2/015 A particle starts from rest at x = -1.8 m and moves along the x-axis with the velocity history shown. Plot the corresponding acceleration and...
A particle moves along the x axis according to the equation x = 1.93 + 2.90t − 1.00t2, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 3.10 s. m (b) Find its velocity at t = 3.10 s. m/s (c) Find its acceleration at t = 3.10 s. m/s2
A particle moves along the x axis according to the equation x = 2.06 + 2.95t - 1.0062, where x is in meters and t is in seconds. (a) Find the position of the particle at t = 2.80 s. m (b) Find its velocity at t = 2.80 s. m/s (c) Find its acceleration at t = 2.80 s. m/s2 Submit Answer
a particle moves along the x axis. its position as a function of time is given by x = 6.8 t + 8.5 t^2 , where t is in seconds and x is in meters. what is the acceleration as a function of time?
A particle moves along the x axis according to the equation x = 1.93 + 2.99t-1.00p, where x is in meters and t is in seconds. (a) Find the position of the particle at t2.60 s. (b) Find its velocity at t -2.60 s m/s (c) Find its acceleration at t-2.60 s m/s2
A 4-kg particle moves along the x-axis under the influence of a conservative force. The potential energy is given by U(x) = bx^3 , where b = 8.0 J/m^3 . What is the magnitude of the acceleration of the particle (in m/s2 ) when it is at the point x = 2 m?
The velocity of a particle moving along the x axis is given for t > 0 by vx = (32.0 − 2.00t2) m/s, where t is in s. What is the acceleration of the particle when (after t = 0) it achieves its maximum displacement in the positive x direction?
A particle starts from the origin at t = 0 and moves along the positive x axis. A graph of the velocity of the particle as a function of the time is shown in the figure; the v-axis scale is set by vs = 6.0 m/s. (a) what is the coordinate of the particle at t = 5.0 s? (b) what is the velocity of the particle at t = 5.0 s? (c) what is the acceleration of the particle...
2. +-12 points PSE6 2.P.015 A particle moves along the x axis according to the equation x-2.073.02t - t2, where x is in meters and t is in seconds. (a) At t 3.40 s, find the position of the particle. (b) What is its velocity? (c) What is its acceleration? m/s m/s2