11.
Solution :- Given that,
Inspiratory time = 1.2 sec
tidal volume = 1.0 L
Flow = ?
Formula :
Inspiratory time = (tidal volume / inspiratory flow)
inspiratory flow= (tidal volume / Inspiratory time)
Inspiratory flow = (1.0/1.2) =0.833 L/sec=49.98 L/min
Inspiratory flow = 49.98 L/min
11. Patient has an inspiratory time 1.2 sec, tidal volume .u What is the flow? 12....
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inspiratory time 1.1 s, tidal volume 0.9 L inspiratory flow rate L/min inspiratory time 0.4 s, tidal volume 200 mL inspiratory flow rate L/min inspiratory time 0.5 s, tidal volume 0.8 L inspiratory flow rate L/min inspiratory time 1.5 s, tidal volume 925 mL inspiratory flow rate te/min Tidal volume 0.9 L, flow rate 45 L/min Inspiratory time is seconds Tidal volume 0.8 L, flow rate 60 L/min Inspiratory time is seconds Tidal volume 700 l-mL, flow rate 42 L/min...
RR 10 breaths/min, I/E ratio is 1:2 Total Cycle Time:_ IT: ET: RR 12 breaths/min, VE ratio is 1:4 Total Cycle Time: IT: ET: RR 20 breaths/min, VE ratio is 1:1 Total Cycle Time: IT: ET: Set RR 15 breaths/min, set Vt 0.82L, flow rate 60 L/min TCT- IT= ET= I/E ratio = Set RR 13 breaths/min, set Vt 750 mL, flow rate 75 L/min VE = TCT IT= ET I/E ratio =
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