Question

If a solution absorbed violet light, what color would the solution appear to be? Hint: Table...

  1. If a solution absorbed violet light, what color would the solution appear to be? Hint: Table I, at the beginning of the experiment, will help you answer this one.

      
  1. Calculate the concentration of a solution prepared by adding 15.00 mL of 1.96×10−31.96×10-3 M KMnO4KMnO4 from a buret into a 50.00 mL volumetric flask, which is then filled to the 50.00 mL graduation mark with distilled water. Hint: This is a dilution calculation.

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  1. A linear standard curve of KMnO4KMnO4 is prepared from a set of standard solutions by plotting absorbance (y) vs. concentration (x). Use Google Sheets/Excel to plot this standard curve using the data in Table 1. Help with spreadsheets [PDF]

Table 1: Data for the standard curve of KMnO4

Absorbance Concentration (M)
0.210 6.00 x 10-4
0.168 4.80 x 10-4
0.126 3.60 x 10-4
0.0840 2.40 x 10-4
0.0420 1.2 x 10-4

After plotting the standard curve, enter its slope below (not the equation of the line). Report your answer to 3 significant figures. If your answer ends in one or more zeros, use scientific notation.

Slope =  M-1

  1. Suppose that an unknown sample is analyzed spectrophotometrically at the same wavelength that was used for the standard curve and the absorbance was found to be 0.196. Use the standard curve to find the concentration of the unknown. Hint: Use y = mx + b to solve for the concentration (x) from the absorbance (y) and the m and b values obtained in question 2.

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Answer #1

Given strength 151) 9.968 10-3 CM) KM nou volume (vi) 15.00 ML diluted volume (V2) = 50.00 mL - New strength (32) = ?? Diluti

y = a + b*x 0.20 Equation Adj. R-Square Intercept Slope Value 2.77556E-1 350 Standard Error 3.0299E-17 7.6129E-14 0.16 Absorbslope = 350 M ( from graph brovided) Absorbance of unknown solution : 0.196: Thus; from y = 350xx tc ; c= 20 775 6 8 10-17 e

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