Question

Calculate the cell potential for this voltaic cell at 25 °C: Cr(s) Cr3 (aq, 0.43 M) || Cl2 (g, 0.771 atm) CI(aq, 0.133 M), Pt

Cas Ze (bp) Cl2(g)+2e 2CI (aq) Cos (aq)+e Co (aq) Co (aq)+2e Co(s) Cr3 (aq)+3e2 Cr(s) Cr3 (aq)+e Cr2 (aq) Cr2 (aq)+ 2e 2Cr(s)

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Answer #1

Reduction half reaction : 301,(8) +6 601 (aq) ; Ethode = 1.358 V Oxidation half reaction: 2Cr(s) —>2C++ (aq) +6e; Egede = -

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