Question

e. From your answers from part C and D above, what is the maximum amount of HCl that could be produced if this reaction was performed with these quantities (5 points)? f. Identify the limiting reactant (the reactant that runs out) (5 points) 5. The above questions walk you through how to solve a limiting reactant problem. Use this same thought process to answer a similar question as it might appear on an exam. (15 points) What is the theoretical Weld, in grams, of magnesium oxide if 2.20 g of magnesium and 6.43 g of oxygen (Os) were allowed to react to form magnesium oxide? 2Mg + O2 → Mgo 6. Based on Question 5, identify the limiting reactant and the reactant that remains in excess. (10 points) Limiting reactant: Reactant in excess: 7. Based on Question 5, how much of the reactant in excess remains when the reaction is complete? (10 points)

Answer 1

5 c०/2: +02 2Mg0 Chiven: magesicmay 6.434 maςς 05 t02) = फरीo mass ot Smoles having less one limiting cageut stoichio. caeffacyt molec ot Magnesium 2-20 mole mass 24 molar masS 6-43 mole mdes ot 04enmass 32 molai mass 2-20 melec stoichiome hc oefficieut 24 72 6t 02 6-41 moles stoichiome bic cotffeu! - 32 t Mg timi heagat Magmesium is limilibg neagei 649en prcsent h AS moles is less shichiometc elc Hence eacess

2M1 t 02 olcess 02 lett moles ob 02 1 moles ot AS Imole ot 02 xcact witu 2 moles 02 lett eliess (6.43 Moles 2.20 24 Y 2 32 0.155 WMoles E0.155 X32 Excess masS oF 02 lett Equation we qet From balanied Brom 2moles fonme d 2 Moles uk Mgo Mao 20rmcd Henie moles ot 2-20 mule 24 2-20 mass 24 3119 yacd ot Mgo 3. (7 Theohitia
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