#4) A planar surface makes an angle 55.0° with a uniform electric field of magnitude 25,000....
#4) A planar surface makes an angle 55.0° with a uniform electric field of magnitude 25,000. N/C as shown in the figure. The surface has an area 0.0280 m2, What is the electric flux through this surface? 55° #5) The total electric flux from a 3-dimensional box with 300 cm on a side is 125 x 103 N charge is enclosed by the box? Permittivity of free space is 8.85 x 10" C'/Nm What
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a plane surface of area 1.63x10-2 m2 What is the electric flux through this surface? N m2/C Submit Request Ans
Suppose a square surface of side 0.10 m is placed in a uniform electric field of magnitude 50.0 N/C. If the angle between the field and the normal to the surface is 25.0°, what is the magnitude of the electric flux through the surface? O 4.5 Nm2/c O 0.45 N-m2/c o.50 N-m2/c o.21 N-m2/c
A uniform electric field of magnitude E = 465 N/C makes an angle of θ = 61.5° with a plane surface of area A = 3.55 m2 as in the figure below. Find the electric flux through this surface.
A uniform electric field of magnitude 2.30×104 N/C makes an angle of 37 ∘ with a plane surface of area 1.60×10−2 m2 . What is the electric flux through this surface? I tried using this equation but it was wrong: (2.30x10^4)(1.60x10^-2)sin(37)= -236.82 Thank you for the help in advance
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude E = 5.20 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. N · m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. N · m2/C
A uniform electric field of magnitude E = 445 N/C makes an angle of theta = 67.0^degree with a plane surface of area A = 3.80 m^2 as in the figure below. Find the electric flux through this surface. N m^2/C
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
A square surface of area 5 cm2 is in a space of uniform electric field of magnitude 104 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux (in N · m2/C) through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180° + θ. (Enter the magnitudes.)...
A uniform electric field of magnitude VC makes an angle of 8 - 64.0 with a plane surface of area A - 3.10 m as in the figure below. Find the electric flux through this surface. Need Help? -15 points SerCP11 15.8.P.045.MI. My Notes Ask Your Teac Meld of intent C) The plane is e d on the to the ye-plane Cathed through a rectangle 30 mwend 0.700 m long i ng conditions are true (n) The plane is parallel...