Question

Pavili O HO OWL2 Online ter * + All the Moon Assignment/takeCovalent Activity do Plocator assignment-taketake AssignmentSessionLocator assignment take Schiometry Review Topics References] Use the References to e mportant values inded for this question For the following reaction, 5.42 grams of nitrogen gas are allowed to react with 5.52 grams of hydrogen gas nitrogen () + hydrogen () - ammonia (g) What is the maximum amount of ammonia that can be formed? What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? Submit Answer Retry Entire Group 7 more group attempts remaining Previous Show in hp

Answer 1

Balancad equation = 28.02 gm Nou, ha max hda mas t= 201588 gmd 5.42 29.02 md 019343320 2 mod of N, 5.52 2.01588md 2-73225213 mt t, 4 н,- 5.52 0.S20299786 ml2.738 25823 mol 0.1934 33241 m *3 N i the liniting neagent 0, he eмсек. Nou, 2 m NH ' Nit heaet , o-1934332 42 mo 6f xo.193472 0.32026524 m ofNtz molas ma No S,0.338L 5 29 md Ntz = 0-3 8¢ 86L 524 mal w 17. 03 6.5883319 04 & ain 0 nia thatF can be formedG-5883369 04 manimum amount imilinneagent N, amoun exeaM H2= 2-732258130.520299721) mdl 2157958444 6l= 2157958444 x201588 gm H amountthe encer heagent H=4.350125208 I = 4350185208