Question

A 2.02 x 10-9 C charge has coordinates x-0, y--2.00; a 2.91 x 10-9 C charge has coordinates x-3.00, y-0; and a -4.60 10-9 C charge has coordinates x 3.00, y-4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin. (a) Determine the magnitude and direction for the electric field at the origin (measure the angle counterclockwise from the positive x-axis). magnitude 6.18e4 NC direction108.03 (b) Determine the magnitude and direction for the instantaneous acceleration of a proton placed at the origin (measure the angle counterclockwise from the positive x-axis) magnitude direction 108.03V
Need help with how you get Part B. How do you find m in the equation a=qe/m as well? Please provide answer and work. Thanks! If correct will give a thumbs up
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Answer #1

C3cm, 4 m) A-chm E3 2 2cm The magnitude oF charges - 2.91 X10-5 C ele ctc fie at onain mashitode) Due to 9.99 Xlo5 x202 x ls 4539.S NIC i, Duc to- K12 - 8- (0.03)23 χ_co mponent of Net electric field at on gin- Es = 45399. 5 + 1454-1.6x 8 32.3 N/c. Nel electnc fed at origih GIG子8.57 N/Coh Scom tas Ccoun ter cloekuwisc) 58632.73 -151 42. ta-J19 142. 59632.^8 The eectic fiad- Thi electic Hdd d a boint is equa

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