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Question 5 (10 points): The number of television viewing hours per household is one factor affecting television advertising income. A random sample of 20 households in a particular viewing area produced the following estimates of viewing hours per household: 3.2 6.0 6.5 8.3 4.2 5.5 6.0 1.0 3.5 4.0 7.5 5.2 9.5 8.0 3.5 9.0 3.0 65 2.4 5.0 (a) Find the mean and standard deviation for these 20 viewing hours per household. To speed up your calculation, you are given Σ. r-683.321 (b) Order the data from smallest to largest (c) Find the z-scores for the smallest and largest viewing hours. Is there any reason to believe that these hours are unusually large or small? Explain

math   Statistics-And-Probability   
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Number of teleuisiom Nie wing hours per hausehalol 3.2 6.0 8.342 1.0 S1 O 95 8.0 3S 31 0 E(H) 07-8 20 2 683 32 2 0 2. 4 3.0 312 1.0 1 2 2 9.sS:39-1.0 2.2613 N20 4:39 2score8.6827 ie 2 score - (8.6827 ) - . d (8.5827 ) is N eelue i e パ·! 2 Jorgest viewing hourm is g.s 212613 |N20 868 1289) 174 there eason--to-believe that these haunt dre when the Sample ize is Jenge enough is-Supposed-thau-tha-sample uc,mance is elmast equel to papwuhion veman (o

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