A tire manufacturing company claims that their tires can be used for at least 150,000 km before they start to wear out. A consumer organization performs a test on the tires. After testing 60 sets, they conclude that the average amount of km the tires can be used, without showing signs of being worn out, is 146,000 km, with a calculated standard deviation of 2000 km. The consumer organization wants to prove that the tires cannot be used for the amount of km that the manufacturer claims. State the hypotheses that need to be tested. Which test should be used? Explain the principle of an ANOVA. That means, what is the theoretical foundation upon which it is based.
The manufacturer claims that their tires can be used for at least 150000 kms before wearing out. We will perform a one-sample t-test to check the same.
Ho: mu <= 150,000
Ha: mu > 150,000
The sample size is 60 sets, n = 60
df = n - 1 = 59
Hence, critical value at df = 59 and alpha = 0.05 is 1.671
t = (X - mu)/(s/√n)
t = (146,000 - 150,000)/(2000/√60)
t = -2√60 = -15.49
As the t-value < +1.671 (one-tailed test), we fail to reject the null hypothesis. We conclude that the manufacturer claim is incorrect.
The principle of ANOVA is to test the differences among the means of two and more populations. The theoretical foundation is that we examine the amount of variation within each of the different samples we have, relative to the amount of variation between the samples.
A tire manufacturing company claims that their tires can be used for at least 150,000 km...
A manufacturer of discount tires announced that its tires can be driven for at least 36,000 miles before wearing out. You suspect that the manufacturer's claim is false and decide to test the tires. In order to determine the average number of miles that discount tires can be driven for, a random sample of 60 tires is selected from the manufacturer's warehouse and the tires are tested independently until they wear out. The sample mean number of miles driven before...
The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60000 miles. Assume the mileage wear follows the normal distribution and the standard deviation of the distribution is 5000 miles. Crosset Truck Company bought 48 tires and found that the mean mileage for its trucks is 59500 miles. Is Crosset’s experience different from that claimed by the manufacturer at the 0.05 significance level? For this...
2. Managers of a transit system want to evaluate four types of tires with respect to wear. Three buses are being used for a test drive with one tire of each type placed randomly on the four wheels of each bus. The tread wear in millimeters 3hj for tire type J installed on bus i is measured after 1000 miles. The data are given in the table below Tire type j Bus 23 4 9.1 17.1 20.8 11.8 13.4 20.3...
A manufacturer of discount tires announced that its tires can be driven for at least 36,000 miles before wearing out. You suspect that the manufacturer's claim is false and decide to test the tires. In order to determine the average number of miles that discount tires can be driven for, a random sample of 60 tires is selected from the manufacturer's warehouse and the tires are tested independently until they wear out. The sample mean number of miles driven before...
The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. Assume the mileage wear follows the normal distribution and the standard deviation of the distribution is 5,000 miles. Crosset Truck Company bought 48 tires and found that the mean mileage for its trucks is 59,500 miles. Crosset would like to know if their experience is different from the manufacturer’s claim. State the null...
It is known that driving can be difficult in regions where winter conditions involve snow-covered roads. For cars equipped with all-season tires traveling at 90 km/hr, the mean stopping distance in fresh snow is known to be 215 meters with a standard deviation of σ = 2.5 meters. It is often advocated that automobiles in such areas should be equipped with special tires to compensate for such conditions, especially with respect to stopping distance. A manufacturer of tires made for...
2-5 Fou x + https:/ ucation The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 milles. Assume the mileage wear follows the normal distribution and the standard deviation of the distribution is 5,000 miles. Crosset Truck Company bought 48 tires and found that the mean mileage for its trucks is 59,500 miles. Crosset would like to know if their experience is different from...
Another 3 more pls guide me with the step
SSCE 2193 c) A company produces metal pipes of a standard length, and claims that the standard deviation of the length is at most 1.1 cm. One of its clients decides to test this claim by taking a sample of 25 pipes and checking their lengths. They found that the standard deviation of the sample is 1.5 cm. Can we accept the company's claim at 2.5% significance level? (5 marks) QUESTION...
A company claims that you can expect your car to get one mpg better gas mileage while using their gasoline additive. A magazine did a study to find out how much a car’s gas mileage improved while using the gasoline additive. The study used 36 cars and recorded the average mpg with and without the additive for each car in the study. The cars with the additive averaged 1.20 mpg better than without and had a variance of 0.36 (mpg)2.a....
The price to earnings ratio (P/E) is an important tool in financial work. A random sample of 14 large U.S. banks (J. P. Morgan, Bank of America, and others) gave the following P/E ratios.† 24 16 22 14 12 13 17 22 15 19 23 13 11 18 The sample mean is x ≈ 17.1. Generally speaking, a low P/E ratio indicates a "value" or bargain stock. Suppose a recent copy of a magazine indicated that the P/E ratio of...