5. A 1.0 mL aliquot of 0.0020 M NaSCN was diluted to 50.0 mL with 0.1...
I. Write the equilibrium constant expression, K for the following reaction Fe"(ag) FENCS(ag) SCN (ag) + CFENCS D 2. In part A of Experiment 34, it was assumed that all of the SCN added to the reaction mixture was converted to product (FeNCS). Which of the following best explains why that assumption was valid? A) The moles of Fe added equaled the moles of SCN- added. B) In part A, the SCN was the limiting reactant whereas in part B,...
A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M NaSCN and 25.0 mL of 0.100 HNO3. The blood-red FeSCN2+ ion forms and the equilibrium is established: Fe3+(aq) + SCN-(aq) <---> FeSCN2+(aq) The equilibrium concentration of FeSCN2+ ([FeSCN2+]) was measured spectrophotometrically and found to be 7.0 x 10-4 mol/L. To calculate the equilibrium constant (Kc) for thr equilibrium system, proceed through the following steps: A. Moles of Fe3+, initial B. Moles of SCN-, initial...
Question 30 of 38 > A 62.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 238 ml. A 119 ml. portion of that solution is diluted by adding 187 mL of water. What is the final concentration? Assume the volumes are additive. concentration:
A 75.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 185 mL of water. What is the final concentration? Assume the volumes are additive. concentration: M
A 50.0 mL sample of 0.436 M NH_4NO_3 is diluted with water to a total volume of 250.6 mL. What is the ammonium nitrate concentration in the resulting solution? 8.72 times 10^-2 M 21.8 M 0.459 M 0.109 M 2.18 times 10^-2 M If 24.95 mL of a 0.1025M HCL solution is added to reach the endpoint of a titration, how many moles of HCl have been added?
A 73.0 ml. aliquot of a 1.30 M solution is diluted to a total volume of 258 ml. A 129 ml. portion of that solution is diluted by kling 135 ml, of water. What is the final concentration? Assume the volumes are additive concentration:
A 69.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 228 mL. A 114 ml. portion of that solution is diluted by adding 131 ml of water. What is the final concentration? Assume the volumes are additive. concentration: 0.157
A 73.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by adding 189 mL of water. What is the final concentration? Assume the volumes are additive.
A 53.0 mL aliquot of a 1.60 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 111 mL of water. What is the final concentration? Assume the volumes are additive.
A 70.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by adding 117 mL of water. What is the final concentration? Assume the volumes are additive.