ΔHo = -19.4 KJ/mol
ΔSo = 92.3 J/mol.K
= 0.0923 KJ/mol.K
T= 25.0 oC
= (25.0+273) K
= 298 K
use:
ΔGo = ΔHo - T*ΔSo
ΔGo = -19.4 - 298.0 * 0.0923
ΔGo = -46.9 KJ/mol
Answer: -46.9 KJ/mol
Determine AGº for the phase change CO2(g) → CO2(aq) at 25°C. AH° = -19.4 kJ/mol AS°...
→ Fe(s) + CO2(g), AGº is - 5.8 kJ and AH° is -11 kJ. Sº (J mol-? K-'); 4. For the reaction Fe(s) + CO(g) Fe (27.3), CO(197.5), CO (213.7) a) What is AS sur? [37 JK-'] b) Use AG to determine whether the reaction is spontaneous or nonspontaneous under standard conditions. Explain. c) Use AS univ to determine whether the reaction is spontaneous or nonspontaneous under standard conditions. Explain. d) What is Sº for FeO? [61 J mol-'K-']
AG°= AH-TAS AG=AGº+RTinQ where R=8.314 J/mol K 1. Calculate AGº for the following reaction at 25 °C if AH°= -1854 kJ/mol; AS°= -236 J/mol K CH-COCH3(g) + 402(g) → 3C02(g) + 3H2O(1) 2. NH.NO, dissolving in water is a spontaneous process. As it dissolves, the temperature of the solution decreases. Based on this, what must the signs (positive or negative) of AG, AH, and AS be?
10. The value of AGº for the Haber reaction, 3H2(g) + N2(g) → 2NH3(g), at 25°C is -32.3 kJ mor! Answer the following: a) Determine the value of Keq for the reaction at 25°C (4 points) b) The value of AH° is-92.2 kJ mor' and the value of AS is -201 J mor' K'Assuming the values of AH° and Asº do not change with temperature, determine agº for the reaction at 475°C. (4 points) c) Determine the value of Key...
), is determined to be -7835.7 kJ mol!! The standard enthalpy change of combustion [to CO2(g) and H200) at 25°C of the organic solid pyrene, CH What is the AH of C16H10(s) based on this value? Use the following data: AH? H20 () --285.83 kJ moll: AH? CO2(8) --393.51 kJ mol! kJ mol!
Question 16 of 45 Submit FeCl3 has a van't Hoff factor of 3.4. What is the freezing point of an aqueous solution made with 1.71 m FeCl3? (Kf for water is 1.86 °C/m) °C 4 7 5 8 6 9 Question 20 of 45 Submit Determine AGº for the phase change CO2(g) → CO2(aq) at 25°C. AH° = -19.4 kJ/mol AS° = +92.3 J/mol-K kJ/mol (1 4 7 +/- 2 5 8 3 6 9 0 x 100 May 7...
llicients. (unbalanced] C2H6(8) + O2(8) — CO2(g) + H2O(g) V C2H6()] = -84.667 kJ/mol Ah (CO2()) = -393.5 kJ/mol AHCO2(aq)] =-412.9 kJ/mol 120(g) = -241.826 kJ/mol AHH,00=-285.840 kJ/mol kJ
5. (opts total) a. For a certain reaction, AH = 142 kJ/mol and AS = - 30.5 J/mol K at 25°C. Calculate the value of AGº for this reaction. Ans: AGº = A different reaction has AH = -106 kJ/mol and AS°= 94.3 J/mol K at 250 Call Ans: AGº = c. Will the reaction in Sa be spontaneous? How can you tell? Will the reaction in 5b be spontaneous? How can you tell?
Determine the enthalpy change for CS20 + 302(g) + CO2(g) + 2SO2(g); AH= ? using the following three thermochemical equations, which will be referred to as reactions (A), (B), and (C). (A) 2C(s) + 202(g) 2002(g); AH= -787.0 kJ (B) C(s) + 25(s) → CS2(); AH= 87.9 kJ (C) SO2(g) → S(s) + O2(g); AH= 296.8 kJ 1. The enthalpy change for the unknown reaction is 2. Describe the action performed on each thermochemical reaction. Reaction (A) was Reaction (B)...
Determine the enthalpy change for C(graphite) + O2(g) → CO2(g); AH= ? using the following three thermochemical equations, which will be referred to as reactions (A), (B), and (C). (A) Sro(s) + CO2(g) → SCO3(s);AH = -234 kJ (B) 2Sro(s) → 25r(s) + O2(g); AH= 1184 kJ (C) 2SrCO3(s) — 25r(s) + 2C(graphite) + 302(g); AH= 2440 kJ The value for AH = List what action you performed on each equation to achieve your goal. Equation (A) was Equation (B)...
(NO(g)) = 20. Determine the enthalpy for the following reaction, given AH (NH3(g)) = -46.1 kJ/mol, AH +90.3 kJ/mol, and AH (H2O(g)) = -241.8 kJ/mol. 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH x = ? kJ a. -1274 kJ/mol d. -905.2 kJ/mol b. -1,996 kJ/mol e. -105.4 kJ/mol c. +1,274 kJ/mol