Question

llicients. (unbalanced] C2H6(8) + O2(8) — CO2(g) + H2O(g) V C2H6()] = -84.667 kJ/mol Ah (CO2()) = -393.5 kJ/mol AHCO2(aq)] =-412.9 kJ/mol 120(g) = -241.826 kJ/mol AHH,00=-285.840 kJ/mol kJ

Answer 1

Answer:

Given chemical equation is

C2H6(g) + O2(g) -------> CO2(g) + H2O(g)

The balanced chemical equation is

2C2H6(g) + 7O2(g) -------> 4CO2(g) + 6H2O(g)

ΔHrxn=Σ n x ΔH^o_f products - Σ m x ΔH^o_f reactants

where n=number of moles of products and m=number of moles of reactants

ΔHrxn= [(4 mol x ΔH^o_f CO2(g)) + (6 mol x ΔH^o_f H2O(g))] - [(2 mol x ΔH^o_f C2H6(g)) + (7 mol x ΔH^o_f O2(g))]

ΔH^o_f C2H6(g)= -84.667 kJ/mol

ΔH^o_f O2(g)= 0 kJ/mol

ΔH^o_f CO2(g)=-393.5 kJ/mol

ΔH^o_f H2O(g)=-241.826 kJ/mol

ΔHrxn= [(4 mol x -393.5 kJ/mol) + (6 mol x -241.826 kJ/mol)] - [(2 mol x -84.667 kJ/mol) + (7 mol x 0 kJ/mol)]

ΔHrxn=-2855.622 kJ.