Homework Answers
Given that, weight percentage = 32.00%
Total mass of solution = 960.0 g
We know that,
Mass percentage = 32.00
(Mass of solute/mass of solution)×100=32.00
(Mass of solute/960.0 g)×100=32.00
Therefore, mass of solute = 307.2g
mass of solute = 307.2 g
Mass of solvent = mass of solution- mass of solute
Mass of solvent = 960.0g- 307.2g
Mass of solvent = 652.8 g .
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12) You are preparing 960.0 grams of an aqueous solution that contains that contains 32.00% by weight of Na2CO3. What mass of solute would you use and what mass of solvent would you use? [4 points) ider 13) What is the weight percent of a calcium chloride (CaCl2] solution that is made by dissolving 151.6 grams of CaCl in 648.4 grams of water? [4 points) 14) Calculate the new molarity of a 20.0-ml sample of 4.50 M MgCl2 solution that...
Determine the following. Please show your work for partial credit and note that, for problems requiring calculations, each correct, but unsupported answer is only worth 1 point. 31)) Determine the new volume (in mL) of a sample of a gas [1.500.0 mL) when conditions are changed from 47.0°C and 28,200 torr to 107.0°C and 47,400 torr? [7 points]
5.00 WS etermine the following. Please show your work for partial credit and note that, for problems requiring lculations, each correct, but unsupported answer is only worth 1 point. :) What would be the reaction product of one mole of potassium hydroxide (KOH) with one mole of aluminum hydroxide (Al(OH)3) and would the resulting product be water soluble? [3 points) ar at a nower plant(e.g., Davis-Besse)
corect, but unsupported answer is only worth I point. your work for partial credit and note that, for probe and note that, for problems requiring The following equation describes the neutraliz hydroxide in aqueous solution: H3PO4 the neutralization of phosphoric acid by the addition of potassium solution: H3PO4 + 3 KOH → K3PO4 + 3H20 of 1.500 M KOH to neutralize 180.0 mL of a given H3PO4 solution, w molarity of this phosphoric acid enlistinn 17 nini If it takes...
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