Question

In order to receive maximum partial credit, please show all work and circle your answers. You must show some work on a problem to receive any credit for that problem. Please express all answers to 3 sig figs. An approved formula sheet is allowed. Problems are worth 17 pt each. Please pay special attention to the units given in each problem. All constants and conversion factors are available on the last page of the test. In Problems 1 & 2, point A is at x = -3.71 cm on the X-axis, point B is at the origin, and point C is at x = +6.43 cm on the X-axis. The charge at point A is -5.38 uc, and the charge at point C is +4.24 uC. 1. Find the magnitude and direction of the net electric field E at point B.

Answer 1

PA =-5-38 4C 2 c = 4.24 MC c( 66.43.19102 A(-3,71,0) B10107 EA - Electric field due to change & at point B = KIZAL EA EC 0-0371 m 0.06437 AB 2c 14 EA = 9x109 xs-38 x16b 10.0371)2 = 35.27100 N &o= Elechic field due to change a at point i Ec = Electric field due to charge de at porntB 72 Tocob42)2 = 9.23810 = K2 = 9x109x4.24 xjö 6 Net Electric field at point B = ² = ELTER È = (-3512x2069 -9129010642 = (-44.43 x'D' 1) * 1 May mitude of net electric field = B = 44-43 x90bN pirection of net elechic field is alonge x dich,