Question

Question: To demonstrate the Doppler effect, your lecturer puts a tone generator playing a 564 Hz tone in a ball tied to a rope and swings it around. As it swings, you hear a maximum frequency of 578 Hz from your seat in the middle of the large lecture hall. Assume the speed of sound through the air is 336 m/s. Part 1) What speed is the ball moving at? v = 8.14 m/s Your last answer was interpreted as follows: 8.14 Part 2) What is the minimum frequency you hear as the ball is swung? min = 550.7 Hz Your last answer was interpreted as follows: 550.7 Part 3) Imagine now that your lecturer performed the same demonstration outside on an oval on a windy day. The wind blows with a speed of 17.7 m/s from behind the lecturer towards you. The lecturer swings the ball in exactly the same way as before. What is the ratio of the new maximum frequency you hear to the maximum frequency you heard inside? foutside, max Jinside, max Check

Answer 1

- a thing way from server observer r = speed of sound in air. . 336 ms. & source. N :- velocity v com ng lowords slagewer vir vesting V coming towards obxeover L - source. V-v B apporent en ball mowing towards observer. f'= 578 fource = 5664 578 = 33€ 564 336-V 1.024 BX 336 - 1.0246N = 336 1 = 8.14 m/s]

Part 3) wind is blow velocity of sound then. ards obreover. towards observer = 336+ 177 = 353.7 m/s foutside = 353.7 froume. 353.7 - 6:14 finside = 336 x frounce 336-8.14 foutside = 336-8.14 = 358.75814 finside 8.949 = 0.949 foutside = finside