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The energy profile of a reaction is shown below. 386 kJ Potential Energy kJ 238 kJ Reaction Pathway What is the activation enRate laws generally take the form Rate = [X]m [Y] ... This question asks about the exponents (m, n, ...) in the ra The react

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386 KT Potential Enel 238KJ Reaction pathoay so, eleally the activation energy E= 386 KJ–238 KJ = 148 KJ = 148 kJ Rate =kboth

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