The energy profile of a reaction is shown below. 386 kJ Potential Energy kJ 238 kJ...
8) A reaction is found to have an activation energy of 38.0 kJ/mol. If the rate constant for this reaction is 1.60 x 102 M-1-1 at 249 K, what is the rate constant at 436 K? 9) If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of 8.0 x 1010 s-1, what is the rate constant for this reaction at 298 K? 10) If the activation energy for a given compound...
21. A reaction proceeds by a series of elementary steps as shown below. The activation energy and heat of reaction are shown for each step. Step No. Elementary step Activation energy Enthalpy of reaction A + B2 → AB, 4 kJ/mol -10 kJ/mol 2 AB2+ C → ABC + BC 30 kJ/mol +5.2 kJ/mol 3 ABC + B2 → AB + BC 10 kJ/mol -7.8 kJ/mol a) What is the overall equation for this reaction? (1 mark) b) What is...
The potential energy profile for the one step reaction AB+CDAC+ BD is shown. The energies are given in units of kJ/mol. What are the values of E, and AE for the REVERSE reaction? 100 80 60 Potential energy 40 20 0 Reaction progress Ea = 60 kJ/mol and AE =-20 kJ/mol O Ea = 80 kJ/mol and AE = 20 kJ/mol Ea = 80 kJ/mol and AE = -20 kJ/mol Ea = 100 kJ/mol and AE = 20 kJ/mol
1) A certain reaction has an activation energy of 67.68 kJ/mol.67.68 kJ/mol. At what Kelvin temperature will the reaction proceed 5.505.50 times faster than it did at 321 K?321 K? T= 2) Consider the elementary reaction equations shown. A(g)+B(g)⟶C(g)+D(g)A(g)+B(g)⟶C(g)+D(g) 2X(g)⟶Y(g)+Z(g)2X(g)⟶Y(g)+Z(g) Write the rate law for reaction A. Write the rate law for reaction B.
1) Calculate the activation energy in kJ/mol for the following reaction if the rate constant for the reaction increases from 93.5 M-1s-1 at 497.7 K to 1349.3 M-1s-1 at 636.7 K. do not include units, but make sure your answer is in kJ/mol! 2) A chemist constructs a plot of ln k vs. 1/T for a chemical reaction. The slope of the trendline for the data is -746 K. What is the activation energy for this reaction in kJ/mol? R...
The activation energy for a reaction is 15 kJ mol-1 at 27° C. A catalyst lowers the activation energy to 10 kJ mol at the same temperature. By what factor is the reaction rate increased? Assume that the reactant concentrations and the pre-exponential factor in the Arrhenius equation are unchanged. O A. 1.5 OB. 1.1 OC. 0.67 O D.7.4 O E. 1.7 x 107 Reset Selection
The activation energy for a particular reaction is 102 kJ/mol. If the rate constant is 1.35 x 10-45-1 at 323 K, what is the rate constant at 273 K? | 1/ Determine the activation energy for the redox reaction Q2+ + 2 R3+ → Q4+ + 2 R2+. Rate Constant Temperature 3.12 x 103 M-15-1 275 K 2.70 x 104 M-15-1 300 K kJ/mol
Question 2 Shown below is the reaction profile for a certain reaction. potential energy im course of reaction (reaction coordinate) How many steps are in this reaction? [Select] How many transition states are featured in this reaction? (Select] Which intermediate is highest in energy? (Select] Is AE positive or negative for this reaction? [Select] Which step is the rate-determining step? [ Select]
4. Suppose that a reaction R → P proceeded according to the energy diagram shown. a. [4 pts] A catalyst lowers the activation barrier of a reaction from 125 kJ/mol to 55 kJ/mol. Write out a reaction mechanism for the catalyzed reaction. b. [6 pts] Sketch what the catalyzed reaction pathway would look like on an energy diagram. All relative heights should make sense for catalyzed pathways for full credit. c. [6 pts] By what factor would you expect the...
1. If the rate constant of a reaction increases by 2.5 when the temperature is increased from 25 C to 34 C, then what is the activation energy (in kJ/mole) of the reactions? 2. If a reaction is first order with a rate constant of 4.48 x 10 ^ -2 sec ^-1, how long is required for 3/4 of the initial concentration of reactant to be used up? 3. Which statement is true or NOT regarding the experimental determination of...