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1. Consider the reaction below for a solution in which the two molecules are both present at 1 mM: R3 R C=O... H-1 C =0 + H-N

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D R (ketane) (Armine) = o H -N :0 TH Ng Dipole Dipde interaction Water Solvent When water will be the solvent, Amine moleculebetween Amire and ketone. * Equilibrium will shift en Backward direction RI SO---H OV HN Thus, Solvent decides the direction

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