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![Date Page No. Reg= [product] , . 40. 4.0 = - RT ln ken T= 25°C 0°C-273k To 25+278= 290k sho = – 8 I x 2984 x molk - - 8 x 290](http://img.homeworklib.com/questions/2a0d5000-1414-11ea-adf6-35b4711f229e.png?x-oss-process=image/resize,w_560)
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Question #2 Consider the following reaction: 1. If a solution of fructose-1-phosphate is incubated with a catalytic amo...
a. through c. please! Question #2 Consider the following reaction: 1. If a solution of fructose-1-phosphate...
a. through c. please!
Question #2 Consider the following reaction: 1. If a solution of fructose-1-phosphate is incubated with a catalytic amount of enzyme X, the fructose-1-phosphate is transformed to fructose-6-phosphate. At equilibrium, the concentrations of the reaction components are fructose-1-phosphate <-> fructose-6-phosphate 10 mM 40 mM a. Calculate K'eq for this reaction at 25°C. b. Calculate AG" for this reaction at 25°C. (use Gas constant-R=8J/molK) c. If the concentration of fructose-1-phosphate is adjusted to 20 M and the concentration...
The difference between AG and AG' (Basic Applied) In glycolysis the following reaction occurs: Fructose 6-phosphate...
The difference between AG and AG' (Basic Applied) In glycolysis the following reaction occurs: Fructose 6-phosphate Glucose 6-phosphate K'eq=1.97 a) What is the AGʻº for the reaction if K'eq is measured at 25°C? (2 points) b) If the concentration of fructose 6-phosphate is 1.5M and that of glucose 6-phosphate is adjusted to 0.50M what is AG? (3 points) c) Why are AG and AG' different? (1 point)
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG...
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for the reaction (K measured at 25 °C)? AG -1680.9 kJ/mol If the concentration of fructose 6-phosphate is adjusted to 1.4 M and that of glucose 6-phosphate is adjusted to 0.75 M, what is AG? AG =-4402.59 kJ/mol Which statements are consistent with the conditions at which AG is measured? The temperature is 273 K. The initial concentrations of reactant and product are 1...
A highly regulated reaction in glycolysis involves the addition of a second phosphate to fructose-6-phosphate, which...
A highly regulated reaction in glycolysis involves the addition
of a second phosphate to fructose-6-phosphate, which could be be
written as:
Fructose-6-phostphate + Pi à Fructose-1,6-bisphosphate + H2O
The ∆Go’ for this reaction is +16.8 kJ/mol
In a muscle cell at 37 oC, assume the concentration of
Fructose-6phosphate is 0.014 mM and the concentration of phosphate
is 1 mM.
a. What would be the equilibrium concentration of
fructose-1,6bisphosphate under these conditions?
b. What is Keq for this reaction?
Show...
the enzyme hexokinase can catalyze the following reaction: fructose + ATP -> fructose 6 phosphate +...
the enzyme hexokinase can catalyze the following
reaction:
fructose + ATP -> fructose 6 phosphate + adp
if the deltaG of hydrolysis of fructose 6 phosphate to
fructose + Pi is -13.8 kj/mol and hydrolysis of atp to adp + pi is
-30kj/mol, calculate Keq for the reaction above (R = 8.31 j mol-1
K-1, T = 298 k
3a. The enzyme hexokinase can catalyze the following reaction: Fructose + ATP → Fructose-6-phosphate + ADP If the ΔGo of hydrolysis...
14. The second step of glycolysis is the following reaction: Glucose-6-phosphate = Fructose-6-phosphate At pH 7...
14. The second step of glycolysis is the following reaction: Glucose-6-phosphate = Fructose-6-phosphate At pH 7 and 25 °C, IM of G6P and F6P will equilibrate to [F6P]/[G6P] = 2.43. R, the molar gas constant, is 8.3145 Jmol'K'. A) What is the standard free energy of this reaction at pH 7 and 25 °C? (2 points) B) In the cell the overall AG is -1400 Jmol"!. Calculate the ratio of products to reactants. (2 points)
Question 4 Q . OH ATP OH POH ОН Fructose 6-phosphate Fructose 1.6-bisphosphate Figure 1. Reaction...
Question 4 Q . OH ATP OH POH ОН Fructose 6-phosphate Fructose 1.6-bisphosphate Figure 1. Reaction catalyzed by phosphofructokinase (PFK) during glycolysis Phosphofructokinase (PFK) is an enzyme that catalyzes the conversion of fructose 6- phosphate to fructose 1,6-bisphosphate during glycolysis, as represented in Figure 1. PFK can be allosterically inhibited by ATP at high concentrations. Which of the following is the benefit of regulating glycolysis by the concentration of ATP? Glycolysis proceeds when the intracellular concentration of ATP is low,...
The enzyme hexokinase catalyzes the following reaction: Glucose + ATP ↔ Glucose 6-phosphate + ADP For...
The enzyme hexokinase catalyzes the following reaction: Glucose + ATP ↔ Glucose 6-phosphate + ADP For this reaction, ΔG° = +16.7 kJ/mol a. Calculate the equilibrium constant for this reaction at 25 °C. Is this reaction spontaneous under standard conditions at this temperature? Calculate the ΔG if the reaction temperature was 25 °C and the concentrations are: glucose, 55.0 mM,; ATP, 5.00 mM; ADP, 1.00 mM; and glucose 6-Phosphate, 0.100 mM. Would the reaction be spontaneous under the conditions of...
1) SHOW WORK 12. During glycolysis, glucose 1-phosphate is converted to fructose 6-phosphate in two successive...
1) SHOW WORK
12. During glycolysis, glucose 1-phosphate is converted to fructose 6-phosphate in two successive reactions: glucose 1-phosphate → glucose 6-phosphate glucose 6-phosphate + fructose 6-phosphate AG'' = -7.1 kJ/mol AG'º = +1.7 kJ/mol 13. The standard free-energy changes for the reactions below are given. phosphocreatine → creatine + Pi ATP → ADP + Pi AG" = 43.0 kJ/mol AG" = -30.5 kJ/mol What is the overall AG' for the following reaction? Iw a dee Hydrolysis of 1 M...
please explain and show calculations Consider the reaction ABB Question 1 1 pts Consider the reaction...
please explain and show calculations
Consider the reaction ABB Question 1 1 pts Consider the reaction above at 27°C with the AGº' = +22,000 J/mol for the forward reaction. The molar concentrations at the beginning of the reaction were [A] = 23 mM and [B] = 4 mm. After 1 hour, the concentrations were [A] = 20 mM and [B] = 10 mM. Gas constant = 8.315 J/mol K Calculate the AG of the reaction after 1 hour. (Round to...
a. through c. please!
Question #2 Consider the following reaction: 1. If a solution of fructose-1-phosphate is incubated with a catalytic amount of enzyme X, the fructose-1-phosphate is transformed to fructose-6-phosphate. At equilibrium, the concentrations of the reaction components are fructose-1-phosphate <-> fructose-6-phosphate 10 mM 40 mM a. Calculate K'eq for this reaction at 25°C. b. Calculate AG" for this reaction at 25°C. (use Gas constant-R=8J/molK) c. If the concentration of fructose-1-phosphate is adjusted to 20 M and the concentration...
The difference between AG and AG' (Basic Applied) In glycolysis the following reaction occurs: Fructose 6-phosphate Glucose 6-phosphate K'eq=1.97 a) What is the AGʻº for the reaction if K'eq is measured at 25°C? (2 points) b) If the concentration of fructose 6-phosphate is 1.5M and that of glucose 6-phosphate is adjusted to 0.50M what is AG? (3 points) c) Why are AG and AG' different? (1 point)
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for the reaction (K measured at 25 °C)? AG -1680.9 kJ/mol If the concentration of fructose 6-phosphate is adjusted to 1.4 M and that of glucose 6-phosphate is adjusted to 0.75 M, what is AG? AG =-4402.59 kJ/mol Which statements are consistent with the conditions at which AG is measured? The temperature is 273 K. The initial concentrations of reactant and product are 1...
A highly regulated reaction in glycolysis involves the addition
of a second phosphate to fructose-6-phosphate, which could be be
written as:
Fructose-6-phostphate + Pi à Fructose-1,6-bisphosphate + H2O
The ∆Go’ for this reaction is +16.8 kJ/mol
In a muscle cell at 37 oC, assume the concentration of
Fructose-6phosphate is 0.014 mM and the concentration of phosphate
is 1 mM.
a. What would be the equilibrium concentration of
fructose-1,6bisphosphate under these conditions?
b. What is Keq for this reaction?
Show...
the enzyme hexokinase can catalyze the following
reaction:
fructose + ATP -> fructose 6 phosphate + adp
if the deltaG of hydrolysis of fructose 6 phosphate to
fructose + Pi is -13.8 kj/mol and hydrolysis of atp to adp + pi is
-30kj/mol, calculate Keq for the reaction above (R = 8.31 j mol-1
K-1, T = 298 k
3a. The enzyme hexokinase can catalyze the following reaction: Fructose + ATP → Fructose-6-phosphate + ADP If the ΔGo of hydrolysis...
14. The second step of glycolysis is the following reaction: Glucose-6-phosphate = Fructose-6-phosphate At pH 7 and 25 °C, IM of G6P and F6P will equilibrate to [F6P]/[G6P] = 2.43. R, the molar gas constant, is 8.3145 Jmol'K'. A) What is the standard free energy of this reaction at pH 7 and 25 °C? (2 points) B) In the cell the overall AG is -1400 Jmol"!. Calculate the ratio of products to reactants. (2 points)
Question 4 Q . OH ATP OH POH ОН Fructose 6-phosphate Fructose 1.6-bisphosphate Figure 1. Reaction catalyzed by phosphofructokinase (PFK) during glycolysis Phosphofructokinase (PFK) is an enzyme that catalyzes the conversion of fructose 6- phosphate to fructose 1,6-bisphosphate during glycolysis, as represented in Figure 1. PFK can be allosterically inhibited by ATP at high concentrations. Which of the following is the benefit of regulating glycolysis by the concentration of ATP? Glycolysis proceeds when the intracellular concentration of ATP is low,...
1) SHOW WORK
12. During glycolysis, glucose 1-phosphate is converted to fructose 6-phosphate in two successive reactions: glucose 1-phosphate → glucose 6-phosphate glucose 6-phosphate + fructose 6-phosphate AG'' = -7.1 kJ/mol AG'º = +1.7 kJ/mol 13. The standard free-energy changes for the reactions below are given. phosphocreatine → creatine + Pi ATP → ADP + Pi AG" = 43.0 kJ/mol AG" = -30.5 kJ/mol What is the overall AG' for the following reaction? Iw a dee Hydrolysis of 1 M...
please explain and show calculations
Consider the reaction ABB Question 1 1 pts Consider the reaction above at 27°C with the AGº' = +22,000 J/mol for the forward reaction. The molar concentrations at the beginning of the reaction were [A] = 23 mM and [B] = 4 mm. After 1 hour, the concentrations were [A] = 20 mM and [B] = 10 mM. Gas constant = 8.315 J/mol K Calculate the AG of the reaction after 1 hour. (Round to...
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