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Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for

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Answer #1

fractose-6-phosphate - glucoll-6-phosphate Keq = 1.97 sa = - RT en keq = -8.314 xib 3x298xIn 1.97 sa -1.68 kg/mol Q - (96-P]

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Answer #2
Consider the following reaction, which occurs in glycolysis: Fructose-6-phosphate ó glucose-6-phosphate (K’eq = 1.97) a) What is DGo’ for the reaction (at 25oC)? b) If the concentration of fructose-6-phosphate is adjusted to 1.5 M and that of glucose-6-phosphate is adjusted to 0.5M, what is DG? c) Why are DGo’ and DG different?
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